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The half life period of first order reaction is 15 min. Its rate constant will be equal to
  • a)
    0.0462 min-1
  • b)
    0.462 min-1
  • c)
    0.00462 min-1
  • d)
    0.562 min-1
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The half life period of first order reaction is 15 min. Its rate const...
The half life of a reaction is 15 min
So,
Here we go..
Formula to be used :

K =0.693/t = 0.693/15
__= 0.462/10 = 0.0462 min^-1
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Community Answer
The half life period of first order reaction is 15 min. Its rate const...
First Order Reaction and Half-Life Period

A first-order reaction is a chemical reaction in which the rate of the reaction is directly proportional to the concentration of the reactant. The half-life period of a reaction is defined as the time required for the concentration of the reactant to decrease to half of its initial value.

Mathematical Expression

The mathematical expression for a first-order reaction is given by:

ln[C]t/[C]0 = -kt

Where [C]t is the concentration of the reactant at time t, [C]0 is the initial concentration of the reactant, k is the rate constant of the reaction, and ln is the natural logarithm.

Calculation of Rate Constant

The half-life period of the reaction is given as 15 minutes. Therefore, we can write:

ln 0.5[C]0/[C]0 = -k(15)

Simplifying the above equation, we get:

ln 0.5 = -k(15)

k = -ln 0.5/15

k = 0.0462 min-1

Therefore, the rate constant of the reaction is 0.0462 min-1.

Answer

Option A is the correct answer: 0.0462 min-1.
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The half life period of first order reaction is 15 min. Its rate constant will be equal toa)0.0462 min-1b)0.462 min-1c)0.00462 min-1d)0.562 min-1Correct answer is option 'A'. Can you explain this answer?
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