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Number of molecules in 1L of water at 4°C is close to: (Give the multiple of NA)
    Correct answer is '55-56'. Can you explain this answer?
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    Number of molecules in 1L of water at 4°C is close to: (Give the m...
    1 lit = 1000 cm3 = 1000 × 1 g = 1000 g = 1000/18 mol =55.5556 mol . It Contain 55.5556 N(A) number of molecule.
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    Number of molecules in 1L of water at 4°C is close to: (Give the m...
    1 lit = 1000 cm3 = 1000 × 1 gm = 1000 gm = 1000/18 mol =55.5556 mol ...it Contain 55.5556 N(A) number of molecule
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    Number of molecules in 1L of water at 4°C is close to: (Give the m...
    To calculate the number of molecules in 1L of water at 4°C, we need to use Avogadro's number and the molar mass of water.

    Avogadro's number (NA) is approximately 6.022 x 10^23 molecules/mol.

    The molar mass of water (H2O) is approximately 18.015 g/mol.

    To convert 1L of water to grams, we need to use the density of water, which is approximately 1 g/mL.

    1L of water is equivalent to 1000 mL.

    Mass of 1L of water = 1000 mL * 1 g/mL = 1000 g.

    Now we can calculate the number of moles of water:

    Number of moles of water = Mass of water / Molar mass of water
    Number of moles of water = 1000 g / 18.015 g/mol ≈ 55.51 mol

    Finally, we can calculate the number of molecules:

    Number of molecules = Number of moles of water * Avogadro's number
    Number of molecules = 55.51 mol * 6.022 x 10^23 molecules/mol ≈ 3.34 x 10^25 molecules

    Therefore, there are approximately 3.34 x 10^25 molecules in 1L of water at 4°C.
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    Number of molecules in 1L of water at 4°C is close to: (Give the multiple of NA)Correct answer is '55-56'. Can you explain this answer?
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