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A compound form hexagonal close packed. What is the total number of voids (up to two decimal places & in the multiple of 1023) in 0.5 mol of it? [rounded up to three decimal places]
Correct answer is between '9.020,9.040'. Can you explain this answer?
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A compound form hexagonal close packed. What is the total number of vo...
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A compound form hexagonal close packed. What is the total number of vo...
Assuming we are talking about a crystal lattice structure, the total number of voids in a hexagonal close packed (HCP) structure can be calculated as follows:
For each unit cell of HCP structure, there are 12 tetrahedral voids and 2 octahedral voids.
The tetrahedral voids are formed by four spheres arranged in a tetrahedral configuration, with the center of the tetrahedron being at the center of the unit cell. There are 6 such tetrahedral voids on the top and bottom faces of the unit cell, and 3 on each of the four side faces, making a total of 12.
The octahedral voids are formed by six spheres arranged in an octahedral configuration, with the center of the octahedron being at the center of the unit cell. There is 1 such octahedral void at the center of the unit cell, and 1 at the midpoint of each of the 12 edges of the unit cell, making a total of 2.
Therefore, the total number of voids in a HCP unit cell is 12 + 2 = 14.
Note: This calculation assumes that all the spheres are of the same size and that they are packed perfectly in a HCP structure. In real-world situations, there may be defects or variations in the size of the spheres, which could affect the number and distribution of voids.
For each unit cell of HCP structure, there are 12 tetrahedral voids and 2 octahedral voids.
The tetrahedral voids are formed by four spheres arranged in a tetrahedral configuration, with the center of the tetrahedron being at the center of the unit cell. There are 6 such tetrahedral voids on the top and bottom faces of the unit cell, and 3 on each of the four side faces, making a total of 12.
The octahedral voids are formed by six spheres arranged in an octahedral configuration, with the center of the octahedron being at the center of the unit cell. There is 1 such octahedral void at the center of the unit cell, and 1 at the midpoint of each of the 12 edges of the unit cell, making a total of 2.
Therefore, the total number of voids in a HCP unit cell is 12 + 2 = 14.
Note: This calculation assumes that all the spheres are of the same size and that they are packed perfectly in a HCP structure. In real-world situations, there may be defects or variations in the size of the spheres, which could affect the number and distribution of voids.
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A compound form hexagonal close packed. What is the total number of vo...
Hexagonal Unit Cell - (z=6)
No. of Octahedral Voids = 6
No. of Tetrahedral Voids = 12
Total effective number of voids (since voids are shared with other unit cells) per unit cell = 3
Per mole of unit cells, there are 3*NA voids = 18.066*10^23
In 0.5mol, there will be 9.033*10^23 voids.
No. of Octahedral Voids = 6
No. of Tetrahedral Voids = 12
Total effective number of voids (since voids are shared with other unit cells) per unit cell = 3
Per mole of unit cells, there are 3*NA voids = 18.066*10^23
In 0.5mol, there will be 9.033*10^23 voids.
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