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A plant virus is found to consist of uniform cylindrical particles of 150 angstrom in diameter and 5000 angstrom long. The specific volume of the virus is 0.75 cm3/g. If the virus is considered to be a single particle, find its molar mass (in g/mol, rounded up to three decimal places, in the multiple of 107):
Correct answer is between '7.000,7.200'. Can you explain this answer?
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A plant virus is found to consist of uniform cylindrical particles of ...
**Given Information:**
- Diameter of the virus particle = 150 angstrom
- Length of the virus particle = 5000 angstrom
- Specific volume of the virus = 0.75 cm^3/g
**Calculating the Volume of the Virus Particle:**
The virus particle is cylindrical in shape. The volume of a cylinder can be calculated using the formula:
Volume = π * (radius)^2 * height
Given that the diameter of the virus particle is 150 angstrom, we can calculate the radius:
Radius = diameter / 2 = 150 angstrom / 2 = 75 angstrom
Converting the radius to centimeters:
Radius = 75 angstrom * (1 cm / 10^8 angstrom) = 7.5 x 10^-7 cm
Using the given length of the virus particle (5000 angstrom), we can calculate the volume:
Volume = π * (7.5 x 10^-7 cm)^2 * 5000 angstrom * (1 cm / 10^8 angstrom)
Converting the volume to cm^3:
Volume = π * (7.5 x 10^-7 cm)^2 * 5000 angstrom * (1 cm / 10^8 angstrom) * (1 cm^3 / 10^-6 cm^3) = 1.767 x 10^-17 cm^3
**Calculating the Mass of the Virus Particle:**
The specific volume of the virus is given as 0.75 cm^3/g. This means that the mass of 1 cm^3 of the virus is 0.75 g.
Mass = Volume * Specific volume = 1.767 x 10^-17 cm^3 * 0.75 g/cm^3 = 1.325 x 10^-17 g
**Calculating the Molar Mass of the Virus Particle:**
The molar mass can be calculated using the formula:
Molar mass = Mass / Number of moles
To find the number of moles, we need to calculate the number of particles in 1 cm^3 of the virus.
Number of particles = Volume of virus / Volume of 1 particle
The volume of 1 particle can be calculated as follows:
Volume of 1 particle = π * (radius)^2 * height = π * (7.5 x 10^-7 cm)^2 * 5000 angstrom * (1 cm / 10^8 angstrom) = 1.767 x 10^-17 cm^3
Number of particles = 1.767 x 10^-17 cm^3 / 1.767 x 10^-17 cm^3 = 1 particle
Therefore, the number of moles = Number of particles / Avogadro's number = 1 particle / 6.022 x 10^23 particles/mol = 1.66 x 10^-24 mol
Now we can calculate the molar mass:
Molar mass = Mass / Number of moles = 1.325 x 10^-17 g / 1.66 x 10^-24 mol = 7.99 x 10^6 g/mol
Rounding up to three decimal places and expressing in multiples of 10^7:
Molar mass = 7.99 x 10^6 g/mol ≈ 7.
- Diameter of the virus particle = 150 angstrom
- Length of the virus particle = 5000 angstrom
- Specific volume of the virus = 0.75 cm^3/g
**Calculating the Volume of the Virus Particle:**
The virus particle is cylindrical in shape. The volume of a cylinder can be calculated using the formula:
Volume = π * (radius)^2 * height
Given that the diameter of the virus particle is 150 angstrom, we can calculate the radius:
Radius = diameter / 2 = 150 angstrom / 2 = 75 angstrom
Converting the radius to centimeters:
Radius = 75 angstrom * (1 cm / 10^8 angstrom) = 7.5 x 10^-7 cm
Using the given length of the virus particle (5000 angstrom), we can calculate the volume:
Volume = π * (7.5 x 10^-7 cm)^2 * 5000 angstrom * (1 cm / 10^8 angstrom)
Converting the volume to cm^3:
Volume = π * (7.5 x 10^-7 cm)^2 * 5000 angstrom * (1 cm / 10^8 angstrom) * (1 cm^3 / 10^-6 cm^3) = 1.767 x 10^-17 cm^3
**Calculating the Mass of the Virus Particle:**
The specific volume of the virus is given as 0.75 cm^3/g. This means that the mass of 1 cm^3 of the virus is 0.75 g.
Mass = Volume * Specific volume = 1.767 x 10^-17 cm^3 * 0.75 g/cm^3 = 1.325 x 10^-17 g
**Calculating the Molar Mass of the Virus Particle:**
The molar mass can be calculated using the formula:
Molar mass = Mass / Number of moles
To find the number of moles, we need to calculate the number of particles in 1 cm^3 of the virus.
Number of particles = Volume of virus / Volume of 1 particle
The volume of 1 particle can be calculated as follows:
Volume of 1 particle = π * (radius)^2 * height = π * (7.5 x 10^-7 cm)^2 * 5000 angstrom * (1 cm / 10^8 angstrom) = 1.767 x 10^-17 cm^3
Number of particles = 1.767 x 10^-17 cm^3 / 1.767 x 10^-17 cm^3 = 1 particle
Therefore, the number of moles = Number of particles / Avogadro's number = 1 particle / 6.022 x 10^23 particles/mol = 1.66 x 10^-24 mol
Now we can calculate the molar mass:
Molar mass = Mass / Number of moles = 1.325 x 10^-17 g / 1.66 x 10^-24 mol = 7.99 x 10^6 g/mol
Rounding up to three decimal places and expressing in multiples of 10^7:
Molar mass = 7.99 x 10^6 g/mol ≈ 7.
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A plant virus is found to consist of uniform cylindrical particles of 150 angstrom in diameter and 5000 angstrom long. The specific volume of the virus is 0.75 cm3/g. If the virus is considered to be a single particle, find its molar mass (in g/mol, rounded up to three decimal places, in the multiple of 107):Correct answer is between '7.000,7.200'. Can you explain this answer?
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A plant virus is found to consist of uniform cylindrical particles of 150 angstrom in diameter and 5000 angstrom long. The specific volume of the virus is 0.75 cm3/g. If the virus is considered to be a single particle, find its molar mass (in g/mol, rounded up to three decimal places, in the multiple of 107):Correct answer is between '7.000,7.200'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A plant virus is found to consist of uniform cylindrical particles of 150 angstrom in diameter and 5000 angstrom long. The specific volume of the virus is 0.75 cm3/g. If the virus is considered to be a single particle, find its molar mass (in g/mol, rounded up to three decimal places, in the multiple of 107):Correct answer is between '7.000,7.200'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A plant virus is found to consist of uniform cylindrical particles of 150 angstrom in diameter and 5000 angstrom long. The specific volume of the virus is 0.75 cm3/g. If the virus is considered to be a single particle, find its molar mass (in g/mol, rounded up to three decimal places, in the multiple of 107):Correct answer is between '7.000,7.200'. Can you explain this answer?.
A plant virus is found to consist of uniform cylindrical particles of 150 angstrom in diameter and 5000 angstrom long. The specific volume of the virus is 0.75 cm3/g. If the virus is considered to be a single particle, find its molar mass (in g/mol, rounded up to three decimal places, in the multiple of 107):Correct answer is between '7.000,7.200'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A plant virus is found to consist of uniform cylindrical particles of 150 angstrom in diameter and 5000 angstrom long. The specific volume of the virus is 0.75 cm3/g. If the virus is considered to be a single particle, find its molar mass (in g/mol, rounded up to three decimal places, in the multiple of 107):Correct answer is between '7.000,7.200'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A plant virus is found to consist of uniform cylindrical particles of 150 angstrom in diameter and 5000 angstrom long. The specific volume of the virus is 0.75 cm3/g. If the virus is considered to be a single particle, find its molar mass (in g/mol, rounded up to three decimal places, in the multiple of 107):Correct answer is between '7.000,7.200'. Can you explain this answer?.
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A plant virus is found to consist of uniform cylindrical particles of 150 angstrom in diameter and 5000 angstrom long. The specific volume of the virus is 0.75 cm3/g. If the virus is considered to be a single particle, find its molar mass (in g/mol, rounded up to three decimal places, in the multiple of 107):Correct answer is between '7.000,7.200'. Can you explain this answer?, a detailed solution for A plant virus is found to consist of uniform cylindrical particles of 150 angstrom in diameter and 5000 angstrom long. The specific volume of the virus is 0.75 cm3/g. If the virus is considered to be a single particle, find its molar mass (in g/mol, rounded up to three decimal places, in the multiple of 107):Correct answer is between '7.000,7.200'. Can you explain this answer? has been provided alongside types of A plant virus is found to consist of uniform cylindrical particles of 150 angstrom in diameter and 5000 angstrom long. The specific volume of the virus is 0.75 cm3/g. If the virus is considered to be a single particle, find its molar mass (in g/mol, rounded up to three decimal places, in the multiple of 107):Correct answer is between '7.000,7.200'. Can you explain this answer? theory, EduRev gives you an
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