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If the body-centered unit cell is assumed to be a cube of edge length ‘a’ with spherical particles of radius ‘r’ then how is the diameter, d of particle and surface area, S of the cell related?
  • a)
    S = 32d4/3
  • b)
    S = 2d2
  • c)
    S = 4d2
  • d)
    S = 8d2
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
If the body-centered unit cell is assumed to be a cube of edge length ...
For BCC unit cell the relation between radius of a particle ‘r’ and edge length of unit cell, a, is r = 
We know that diameter, d = 2r =
Implying d2 =
Therefore, 4d2/3=a2
Multiplying by 6 on both sides gives S = 6a2 = 8d2, where S is the surface area of the cube = 6a2.
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Community Answer
If the body-centered unit cell is assumed to be a cube of edge length ...
$a$, then the body diagonal of the cube is equal to $\sqrt{3}a$.
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If the body-centered unit cell is assumed to be a cube of edge length ‘a’ with spherical particles of radius ‘r’ then how is the diameter, d of particle and surface area, S of the cell related?a)S = 32d4/3b)S = 2d2c)S = 4d2d)S = 8d2Correct answer is option 'D'. Can you explain this answer?
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If the body-centered unit cell is assumed to be a cube of edge length ‘a’ with spherical particles of radius ‘r’ then how is the diameter, d of particle and surface area, S of the cell related?a)S = 32d4/3b)S = 2d2c)S = 4d2d)S = 8d2Correct answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about If the body-centered unit cell is assumed to be a cube of edge length ‘a’ with spherical particles of radius ‘r’ then how is the diameter, d of particle and surface area, S of the cell related?a)S = 32d4/3b)S = 2d2c)S = 4d2d)S = 8d2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the body-centered unit cell is assumed to be a cube of edge length ‘a’ with spherical particles of radius ‘r’ then how is the diameter, d of particle and surface area, S of the cell related?a)S = 32d4/3b)S = 2d2c)S = 4d2d)S = 8d2Correct answer is option 'D'. Can you explain this answer?.
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