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A 0.1 M solution of compound A shows 50% transmittance when a cell of 1 cm width is used at λ1 nm. Another 0.1 M solution of compound B gives the optical density value of 0.1761 using 1cm cell at λ1 nm. What will be the transmittance of a solution that is simultaneously 0.1 M in A and 0.1 M in B using the same cell and at the same wave length? [log 1.301; log 1.4771; log 50 = 1.699]. (rounded up to two decimal places)
Correct answer is between '0.32,0.34'. Can you explain this answer?
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A certain wavelength. What is the molar absorptivity of compound A at that wavelength?
Molar absorptivity (ε) is defined as the ability of a substance to absorb light at a specific wavelength per unit concentration. It is calculated using the Beer-Lambert law:
A = ε l c
where A is the absorbance, ε is the molar absorptivity, l is the path length (in this case, 1 cm), and c is the concentration in moles per liter (M).
Transmittance (T) is the fraction of light that passes through a sample, and is related to absorbance by:
T = 10^(-A)
At 50% transmittance, T = 0.5, and therefore A = -log(T) = -log(0.5) = 0.301.
Substituting the values into the Beer-Lambert law:
0.301 = ε x 1 x 0.1
Solving for ε:
ε = 0.301 / (1 x 0.1) = 3.01 L mol^(-1) cm^(-1)
Therefore, the molar absorptivity of compound A at that wavelength is 3.01 L mol^(-1) cm^(-1).
Molar absorptivity (ε) is defined as the ability of a substance to absorb light at a specific wavelength per unit concentration. It is calculated using the Beer-Lambert law:
A = ε l c
where A is the absorbance, ε is the molar absorptivity, l is the path length (in this case, 1 cm), and c is the concentration in moles per liter (M).
Transmittance (T) is the fraction of light that passes through a sample, and is related to absorbance by:
T = 10^(-A)
At 50% transmittance, T = 0.5, and therefore A = -log(T) = -log(0.5) = 0.301.
Substituting the values into the Beer-Lambert law:
0.301 = ε x 1 x 0.1
Solving for ε:
ε = 0.301 / (1 x 0.1) = 3.01 L mol^(-1) cm^(-1)
Therefore, the molar absorptivity of compound A at that wavelength is 3.01 L mol^(-1) cm^(-1).
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A 0.1 M solution of compound A shows 50% transmittance when a cell of 1 cm width is used at λ1nm. Another 0.1 M solution of compound B gives the optical density value of 0.1761 using 1cm cell at λ1nm. What will be the transmittance of a solution that is simultaneously 0.1 M in A and 0.1 M in B using the same cell and at the same wave length? [log 1.301; log 1.4771; log 50 = 1.699]. (rounded up to two decimal places)Correct answer is between '0.32,0.34'. Can you explain this answer?
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A 0.1 M solution of compound A shows 50% transmittance when a cell of 1 cm width is used at λ1nm. Another 0.1 M solution of compound B gives the optical density value of 0.1761 using 1cm cell at λ1nm. What will be the transmittance of a solution that is simultaneously 0.1 M in A and 0.1 M in B using the same cell and at the same wave length? [log 1.301; log 1.4771; log 50 = 1.699]. (rounded up to two decimal places)Correct answer is between '0.32,0.34'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A 0.1 M solution of compound A shows 50% transmittance when a cell of 1 cm width is used at λ1nm. Another 0.1 M solution of compound B gives the optical density value of 0.1761 using 1cm cell at λ1nm. What will be the transmittance of a solution that is simultaneously 0.1 M in A and 0.1 M in B using the same cell and at the same wave length? [log 1.301; log 1.4771; log 50 = 1.699]. (rounded up to two decimal places)Correct answer is between '0.32,0.34'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 0.1 M solution of compound A shows 50% transmittance when a cell of 1 cm width is used at λ1nm. Another 0.1 M solution of compound B gives the optical density value of 0.1761 using 1cm cell at λ1nm. What will be the transmittance of a solution that is simultaneously 0.1 M in A and 0.1 M in B using the same cell and at the same wave length? [log 1.301; log 1.4771; log 50 = 1.699]. (rounded up to two decimal places)Correct answer is between '0.32,0.34'. Can you explain this answer?.
A 0.1 M solution of compound A shows 50% transmittance when a cell of 1 cm width is used at λ1nm. Another 0.1 M solution of compound B gives the optical density value of 0.1761 using 1cm cell at λ1nm. What will be the transmittance of a solution that is simultaneously 0.1 M in A and 0.1 M in B using the same cell and at the same wave length? [log 1.301; log 1.4771; log 50 = 1.699]. (rounded up to two decimal places)Correct answer is between '0.32,0.34'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A 0.1 M solution of compound A shows 50% transmittance when a cell of 1 cm width is used at λ1nm. Another 0.1 M solution of compound B gives the optical density value of 0.1761 using 1cm cell at λ1nm. What will be the transmittance of a solution that is simultaneously 0.1 M in A and 0.1 M in B using the same cell and at the same wave length? [log 1.301; log 1.4771; log 50 = 1.699]. (rounded up to two decimal places)Correct answer is between '0.32,0.34'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 0.1 M solution of compound A shows 50% transmittance when a cell of 1 cm width is used at λ1nm. Another 0.1 M solution of compound B gives the optical density value of 0.1761 using 1cm cell at λ1nm. What will be the transmittance of a solution that is simultaneously 0.1 M in A and 0.1 M in B using the same cell and at the same wave length? [log 1.301; log 1.4771; log 50 = 1.699]. (rounded up to two decimal places)Correct answer is between '0.32,0.34'. Can you explain this answer?.
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