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Consider a titration of Potassium dichromate solution with acidified Mohr’s salt solution using diphenylamine as indicator. The number of moles of Mohr’s salt required per mole of dichromate is:
  • a)
    3
  • b)
    4
  • c)
    6
  • d)
    5
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Consider a titration of Potassium dichromate solution with acidified M...
In the redox reaction, Cr2O2−7 oxidises Mohr's salt, FeSO4.(NH4)2SO4.6H2O
6Fe2++Cr2O2−7+14H+⟶6Fe3++2Cr3+7H2O
Mohr's salt [FeSO4.(NH4)2SO4.6H2O] and
dichromate reacts in 6:1 molar ratio . or one more of Cr2O2−7 will require six moles of Fe2+ ions
Hence C is the correct answer.
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Consider a titration of Potassium dichromate solution with acidified M...
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Consider a titration of Potassium dichromate solution with acidified Mohr’s salt solution usingdiphenylamine as indicator. The number of moles of Mohr’s salt required per mole of dichromate is:a)3b)4c)6d)5Correct answer is option 'C'. Can you explain this answer?
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Consider a titration of Potassium dichromate solution with acidified Mohr’s salt solution usingdiphenylamine as indicator. The number of moles of Mohr’s salt required per mole of dichromate is:a)3b)4c)6d)5Correct answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Consider a titration of Potassium dichromate solution with acidified Mohr’s salt solution usingdiphenylamine as indicator. The number of moles of Mohr’s salt required per mole of dichromate is:a)3b)4c)6d)5Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a titration of Potassium dichromate solution with acidified Mohr’s salt solution usingdiphenylamine as indicator. The number of moles of Mohr’s salt required per mole of dichromate is:a)3b)4c)6d)5Correct answer is option 'C'. Can you explain this answer?.
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