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Chemistry Exam  >  Chemistry Questions  >  In [Cr(O2)(NH3)4(H2O)]Cl2, oxidation number o... Start Learning for Free
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In [Cr(O2)(NH3)4(H2O)]Cl2, oxidation number of Cr is +3, the, O2 will be in form:           
  • a)
    Dioxo                          
  • b)
    Peroxo                           
  • c)
    Superoxo                  
  • d)
    Oxo
Correct answer is option 'C'. Can you explain this answer?
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In [Cr(O2)(NH3)4(H2O)]Cl2, oxidation number of Cr is +3, the, O2 will ...
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In [Cr(O2)(NH3)4(H2O)]Cl2, oxidation number of Cr is +3, the, O2 will ...
In the above compound, Cr is in +3 oxidation state is given. the oxidation state of Cl is -1 so the charge on coordination sphere will be +2 since NH3 and H2O have zero charge and Cr has +3 so O2 has -1 charge so that the overall charge on coordination sphere comes out to be +2. and o2 with -1 charge is called superoxo
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In [Cr(O2)(NH3)4(H2O)]Cl2, oxidation number of Cr is +3, the, O2 will ...
Explanation:

In the given complex [Cr(O2)(NH3)4(H2O)]Cl2, the oxidation number of Cr is +3.

Oxidation number of Cr:
To determine the oxidation number of Cr, we assign oxidation numbers to the other elements in the compound and then solve for the unknown.

Let's assign oxidation numbers to the known elements:
- The oxidation number of O is usually -2 in compounds, so the total oxidation number of O2 is -4.
- The oxidation number of H is +1 in compounds.
- The oxidation number of Cl is -1 in compounds.

Now, let's calculate the oxidation number of Cr:
- Since there are 4 NH3 ligands, and the oxidation number of H is +1, the total oxidation number of NH3 is +4.
- Since there is 1 H2O ligand, and the oxidation number of H is +1, the total oxidation number of H2O is +1.
- Let the oxidation number of Cr be x.

According to the given complex:
(+3) + (x) + (-4) + (+4) + (+1) + (-2) = 0
Simplifying the equation, we get:
x + 2 = 0
x = -2

Therefore, the oxidation number of Cr is +3.

O2 ligand:
The O2 ligand in the complex has an oxidation number of -1. This is because the oxidation number of O is usually -2 in compounds, and since there are two O atoms in the O2 ligand, the total oxidation number of O2 is -2. Since the overall charge of the O2 ligand is -1, the oxidation number of O in the O2 ligand is -1.

Conclusion:
In the complex [Cr(O2)(NH3)4(H2O)]Cl2, the oxidation number of Cr is +3 and the O2 ligand is in the form of superoxo (superoxide) with an oxidation number of -1.
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In [Cr(O2)(NH3)4(H2O)]Cl2, oxidation number of Cr is +3, the, O2 will be in form:a)Dioxob)Peroxoc)Superoxod)OxoCorrect answer is option 'C'. Can you explain this answer?
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