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A motor boat starting from a rest on a lake accelerate in a straight line at a constant rate of 2m/s for at 8 sec how for the boat travel during this time
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A motor boat starting from a rest on a lake accelerate in a straight l...
From 2nd equation of motion
s=ut+1/2 at^2
s=0×t+1/2×2×8×8
s=64m.
s=ut+1/2 at^2
s=0×t+1/2×2×8×8
s=64m.
Community Answer
A motor boat starting from a rest on a lake accelerate in a straight l...
Initial Situation:
The motorboat starts from rest on a lake.
Acceleration:
The boat accelerates in a straight line at a constant rate of 2 m/s² for 8 seconds.
Formula for Distance Travelled:
To calculate the distance travelled by the boat during this time, we can use the formula:
\[ s = ut + \frac{1}{2}at^2 \]
where:
s = distance travelled,
u = initial velocity (0 m/s as the boat starts from rest),
a = acceleration (2 m/s²),
t = time taken (8 seconds).
Calculation:
Plugging in the values:
\[ s = 0 \times 8 + \frac{1}{2} \times 2 \times (8)^2 \]
\[ s = 0 + \frac{1}{2} \times 2 \times 64 \]
\[ s = 0 + 64 \]
\[ s = 64 \text{ meters} \]
Therefore, the boat travels a distance of 64 meters during the 8 seconds of constant acceleration.
The motorboat starts from rest on a lake.
Acceleration:
The boat accelerates in a straight line at a constant rate of 2 m/s² for 8 seconds.
Formula for Distance Travelled:
To calculate the distance travelled by the boat during this time, we can use the formula:
\[ s = ut + \frac{1}{2}at^2 \]
where:
s = distance travelled,
u = initial velocity (0 m/s as the boat starts from rest),
a = acceleration (2 m/s²),
t = time taken (8 seconds).
Calculation:
Plugging in the values:
\[ s = 0 \times 8 + \frac{1}{2} \times 2 \times (8)^2 \]
\[ s = 0 + \frac{1}{2} \times 2 \times 64 \]
\[ s = 0 + 64 \]
\[ s = 64 \text{ meters} \]
Therefore, the boat travels a distance of 64 meters during the 8 seconds of constant acceleration.
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A motor boat starting from a rest on a lake accelerate in a straight line at a constant rate of 2m/s for at 8 sec how for the boat travel during this time Related: NCERT Solutions - Motion, Class 9, Science
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