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Calculate the pressure exerted by one mole of CO2 gas at 273 K, if the van der Waals’ constant ‘a’ = 3.592 dm6 atm mol–2. Assume that the volume occupied by CO2 molecules is negligible.
Correct answer is '34.98'. Can you explain this answer?
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Calculate the pressure exerted by one mole of CO2 gas at 273 K, if the...
Ans.
According to Van Der waal’s equation
(for 1 mole of the gas)
Since,the volume occupied by CO2 molecules is negligible, therefore, b =o
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Calculate the pressure exerted by one mole of CO2 gas at 273 K, if the...
Equation of state is used with the following values for CO2: a = 3.592 L^2 atm/mol^2 and b = 0.0427 L/mol.
The van der Waals equation of state is:
(P + a(n/V)^2)(V - nb) = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.08206 L atm/mol K), T is the temperature in Kelvin, a is the attractive force constant, and b is the volume of the molecules.
We are given that we have one mole of CO2 gas at 273 K. We can assume that the volume is 1 L since we have one mole. Therefore, we can rewrite the equation as:
(P + a/V^2)(V - b) = RT
Substituting in the values given for CO2, we get:
(P + (3.592 L^2 atm/mol^2)/(1 L)^2)(1 L - 0.0427 L) = (1 mol)(0.08206 L atm/mol K)(273 K)
Simplifying:
(P + 14.384 atm)(0.9573 L) = 22.414 L atm/mol
P + 13.783 atm = 23.357 atm
P = 9.574 atm
Therefore, the pressure exerted by one mole of CO2 gas at 273 K using the van der Waals equation of state is 9.574 atm.
The van der Waals equation of state is:
(P + a(n/V)^2)(V - nb) = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.08206 L atm/mol K), T is the temperature in Kelvin, a is the attractive force constant, and b is the volume of the molecules.
We are given that we have one mole of CO2 gas at 273 K. We can assume that the volume is 1 L since we have one mole. Therefore, we can rewrite the equation as:
(P + a/V^2)(V - b) = RT
Substituting in the values given for CO2, we get:
(P + (3.592 L^2 atm/mol^2)/(1 L)^2)(1 L - 0.0427 L) = (1 mol)(0.08206 L atm/mol K)(273 K)
Simplifying:
(P + 14.384 atm)(0.9573 L) = 22.414 L atm/mol
P + 13.783 atm = 23.357 atm
P = 9.574 atm
Therefore, the pressure exerted by one mole of CO2 gas at 273 K using the van der Waals equation of state is 9.574 atm.
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Calculate the pressure exerted by one mole of CO2 gas at 273 K, if the van der Waals’ constant ‘a’ = 3.592 dm6 atm mol–2. Assume that the volume occupied by CO2 molecules is negligible.Correct answer is '34.98'. Can you explain this answer?
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Calculate the pressure exerted by one mole of CO2 gas at 273 K, if the van der Waals’ constant ‘a’ = 3.592 dm6 atm mol–2. Assume that the volume occupied by CO2 molecules is negligible.Correct answer is '34.98'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Calculate the pressure exerted by one mole of CO2 gas at 273 K, if the van der Waals’ constant ‘a’ = 3.592 dm6 atm mol–2. Assume that the volume occupied by CO2 molecules is negligible.Correct answer is '34.98'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the pressure exerted by one mole of CO2 gas at 273 K, if the van der Waals’ constant ‘a’ = 3.592 dm6 atm mol–2. Assume that the volume occupied by CO2 molecules is negligible.Correct answer is '34.98'. Can you explain this answer?.
Calculate the pressure exerted by one mole of CO2 gas at 273 K, if the van der Waals’ constant ‘a’ = 3.592 dm6 atm mol–2. Assume that the volume occupied by CO2 molecules is negligible.Correct answer is '34.98'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Calculate the pressure exerted by one mole of CO2 gas at 273 K, if the van der Waals’ constant ‘a’ = 3.592 dm6 atm mol–2. Assume that the volume occupied by CO2 molecules is negligible.Correct answer is '34.98'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the pressure exerted by one mole of CO2 gas at 273 K, if the van der Waals’ constant ‘a’ = 3.592 dm6 atm mol–2. Assume that the volume occupied by CO2 molecules is negligible.Correct answer is '34.98'. Can you explain this answer?.
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