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The compression factor (compressibility factor) for one mole of a van der Waals’ gas at 0°C and 100 atm pressure is found to be 0.5. Assume that the volume of a gas molecule is negligible, calculate the van der Waals’ constant ‘a’
Correct answer is '1.253'. Can you explain this answer?
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The compression factor (compressibility factor) for one mole of a van ...
We know that, Compressibility factor, Z = PV/RT
0.5 = 100 *V/0.082 *273
∴ V = 0.1117L
NOTE : Further when volume of a gas molecule is negligible, van der Waal’s equation becomes
(P + a/V2) (V - 0) = RT
Or PV = RT – a/V or a = RTV – PV2
Substituting the values
A = (0.082 * 0.1119 *273) – (100 * 0.1119 * 0.1119)
= 1.253 atm L2 mol-2
Most Upvoted Answer
The compression factor (compressibility factor) for one mole of a van ...
S gas is given by the equation:
Z = (P + a/V^2)(V - b) / RT
Where:
Z is the compressibility factor
P is the pressure
V is the volume
a and b are van der Waals constants
R is the ideal gas constant
T is the temperature
The van der Waals equation is an improvement upon the ideal gas law, taking into account the attractive forces between gas molecules (represented by the term -a/V^2) and the volume occupied by the gas molecules themselves (represented by the term b). The compressibility factor Z adjusts the ideal gas law to account for these non-ideal behaviors.
The compressibility factor Z can be used to determine if a gas behaves more like an ideal gas (Z close to 1) or exhibits significant deviations from ideal behavior (Z significantly different from 1).
Z = (P + a/V^2)(V - b) / RT
Where:
Z is the compressibility factor
P is the pressure
V is the volume
a and b are van der Waals constants
R is the ideal gas constant
T is the temperature
The van der Waals equation is an improvement upon the ideal gas law, taking into account the attractive forces between gas molecules (represented by the term -a/V^2) and the volume occupied by the gas molecules themselves (represented by the term b). The compressibility factor Z adjusts the ideal gas law to account for these non-ideal behaviors.
The compressibility factor Z can be used to determine if a gas behaves more like an ideal gas (Z close to 1) or exhibits significant deviations from ideal behavior (Z significantly different from 1).
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The compression factor (compressibility factor) for one mole of a van der Waals’ gas at 0°C and 100 atm pressure is found to be 0.5. Assume that the volume of a gas molecule is negligible, calculate the van der Waals’ constant ‘a’Correct answer is '1.253'. Can you explain this answer?
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The compression factor (compressibility factor) for one mole of a van der Waals’ gas at 0°C and 100 atm pressure is found to be 0.5. Assume that the volume of a gas molecule is negligible, calculate the van der Waals’ constant ‘a’Correct answer is '1.253'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The compression factor (compressibility factor) for one mole of a van der Waals’ gas at 0°C and 100 atm pressure is found to be 0.5. Assume that the volume of a gas molecule is negligible, calculate the van der Waals’ constant ‘a’Correct answer is '1.253'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The compression factor (compressibility factor) for one mole of a van der Waals’ gas at 0°C and 100 atm pressure is found to be 0.5. Assume that the volume of a gas molecule is negligible, calculate the van der Waals’ constant ‘a’Correct answer is '1.253'. Can you explain this answer?.
The compression factor (compressibility factor) for one mole of a van der Waals’ gas at 0°C and 100 atm pressure is found to be 0.5. Assume that the volume of a gas molecule is negligible, calculate the van der Waals’ constant ‘a’Correct answer is '1.253'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The compression factor (compressibility factor) for one mole of a van der Waals’ gas at 0°C and 100 atm pressure is found to be 0.5. Assume that the volume of a gas molecule is negligible, calculate the van der Waals’ constant ‘a’Correct answer is '1.253'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The compression factor (compressibility factor) for one mole of a van der Waals’ gas at 0°C and 100 atm pressure is found to be 0.5. Assume that the volume of a gas molecule is negligible, calculate the van der Waals’ constant ‘a’Correct answer is '1.253'. Can you explain this answer?.
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