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ABCD is a parallelogram in which DC is produced to P such that DC = CP. AP intersects BC at Q. If ar(△BQD) = 3cm2,then ar(║ABCD) is
  • a)
    15cm2.
  • b)
    6cm2.
  • c)
    9cm2.
  • d)
    12cm2.
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
ABCD is a parallelogram in which DC is produced to P such that DC = CP...
By cons draw qf parallel and equal to DC.dcq=bad. prove qcp congruent to abq so q is midpoint hence area of 2parallelograw drawn by cons is equalar of first =2(3)=6
total area of parallelogram is equal to 2(dcqd)
total area =12 cm sq
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ABCD is a parallelogram in which DC is produced to P such that DC = CP. AP intersects BC at Q. Ifar(△BQD) = 3cm2,thenar(║ABCD) isa)15cm2.b)6cm2.c)9cm2.d)12cm2.Correct answer is option 'C'. Can you explain this answer?
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