JEE Exam > JEE Questions > Ethyl alcohol on oxidation with K₂Cr₂O₇ gives...
Start Learning for Free
Ethyl alcohol on oxidation with K₂Cr₂O₇ gives
- a)Acetic acid
- b)Acetaldehyde
- c)Formaldehyde
- d)Formic acid
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
Ethyl alcohol on oxidation with K₂Cr₂O₇ givesa) ...
Oxidation of Ethyl Alcohol with KCrO4 to form Acetic Acid
Oxidation of Ethyl Alcohol with Potassium Dichromate (K2Cr2O7) is a redox reaction. In this reaction, ethyl alcohol is oxidized to acetic acid by the strong oxidizing agent potassium dichromate. The process of oxidizing alcohol is a common reaction in organic chemistry.
The balanced chemical equation for the reaction is given as follows:
3 CH3CH2OH + 2 K2Cr2O7 + 8 H2SO4 → 3 CH3COOH + 2 Cr2(SO4)3 + 2 K2SO4 + 11 H2O
Explanation of the reaction:
- In the reaction, potassium dichromate acts as a strong oxidizing agent.
- Ethyl alcohol is a primary alcohol and it can be converted to an aldehyde or a carboxylic acid by oxidation.
- However, in the presence of strong oxidizing agents like potassium dichromate, the oxidation of alcohol goes all the way to the carboxylic acid stage.
- The oxidation is carried out in the presence of sulfuric acid, which acts as a catalyst.
- The reaction is exothermic and the heat evolved is sufficient to boil the water and sulfuric acid mixture.
- The reaction mixture is then cooled and the acetic acid is purified by distillation.
Conclusion
Hence, option A, i.e., acetic acid is the correct answer.
Oxidation of Ethyl Alcohol with Potassium Dichromate (K2Cr2O7) is a redox reaction. In this reaction, ethyl alcohol is oxidized to acetic acid by the strong oxidizing agent potassium dichromate. The process of oxidizing alcohol is a common reaction in organic chemistry.
The balanced chemical equation for the reaction is given as follows:
3 CH3CH2OH + 2 K2Cr2O7 + 8 H2SO4 → 3 CH3COOH + 2 Cr2(SO4)3 + 2 K2SO4 + 11 H2O
Explanation of the reaction:
- In the reaction, potassium dichromate acts as a strong oxidizing agent.
- Ethyl alcohol is a primary alcohol and it can be converted to an aldehyde or a carboxylic acid by oxidation.
- However, in the presence of strong oxidizing agents like potassium dichromate, the oxidation of alcohol goes all the way to the carboxylic acid stage.
- The oxidation is carried out in the presence of sulfuric acid, which acts as a catalyst.
- The reaction is exothermic and the heat evolved is sufficient to boil the water and sulfuric acid mixture.
- The reaction mixture is then cooled and the acetic acid is purified by distillation.
Conclusion
Hence, option A, i.e., acetic acid is the correct answer.
Free Test
FREE
| Start Free Test |
Community Answer
Ethyl alcohol on oxidation with K₂Cr₂O₇ givesa) ...
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
Ethyl alcohol on oxidation with K₂Cr₂O₇ givesa) Acetic acid b) Acetaldehyde c) Formaldehyde d) Formic acid Correct answer is option 'A'. Can you explain this answer?
Question Description
Ethyl alcohol on oxidation with K₂Cr₂O₇ givesa) Acetic acid b) Acetaldehyde c) Formaldehyde d) Formic acid Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Ethyl alcohol on oxidation with K₂Cr₂O₇ givesa) Acetic acid b) Acetaldehyde c) Formaldehyde d) Formic acid Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ethyl alcohol on oxidation with K₂Cr₂O₇ givesa) Acetic acid b) Acetaldehyde c) Formaldehyde d) Formic acid Correct answer is option 'A'. Can you explain this answer?.
Ethyl alcohol on oxidation with K₂Cr₂O₇ givesa) Acetic acid b) Acetaldehyde c) Formaldehyde d) Formic acid Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Ethyl alcohol on oxidation with K₂Cr₂O₇ givesa) Acetic acid b) Acetaldehyde c) Formaldehyde d) Formic acid Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ethyl alcohol on oxidation with K₂Cr₂O₇ givesa) Acetic acid b) Acetaldehyde c) Formaldehyde d) Formic acid Correct answer is option 'A'. Can you explain this answer?.
Solutions for Ethyl alcohol on oxidation with K₂Cr₂O₇ givesa) Acetic acid b) Acetaldehyde c) Formaldehyde d) Formic acid Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Ethyl alcohol on oxidation with K₂Cr₂O₇ givesa) Acetic acid b) Acetaldehyde c) Formaldehyde d) Formic acid Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Ethyl alcohol on oxidation with K₂Cr₂O₇ givesa) Acetic acid b) Acetaldehyde c) Formaldehyde d) Formic acid Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Ethyl alcohol on oxidation with K₂Cr₂O₇ givesa) Acetic acid b) Acetaldehyde c) Formaldehyde d) Formic acid Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Ethyl alcohol on oxidation with K₂Cr₂O₇ givesa) Acetic acid b) Acetaldehyde c) Formaldehyde d) Formic acid Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Ethyl alcohol on oxidation with K₂Cr₂O₇ givesa) Acetic acid b) Acetaldehyde c) Formaldehyde d) Formic acid Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup