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The complex that shows orbital contribution to the magnetic moment, is           
  • a)
    [Cu(H2O)6]2+                 
  • b)
    [Ni(H2O)6]2+              
  • c)
    [Co(H2O)6]2+           
  • d)
    [Cr(H2O)6]2+
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The complex that shows orbital contribution to the magnetic moment, is...
Orbital Contribution to Magnetic Moment in [Co(H2O)6]2+

Explanation:
When a complex is placed in an external magnetic field, the electrons experience a force that causes them to align their spins in parallel or antiparallel directions. This alignment results in a net magnetic moment for the complex.

There are two types of contributions to the magnetic moment of a complex: spin-only and orbital. Spin-only contribution arises due to the spin of the electrons, while the orbital contribution arises due to the motion of the electrons in the magnetic field.

In [Co(H2O)6]2+, the cobalt ion has a d6 electronic configuration with 4 unpaired electrons. The ground state of the complex is a high-spin state, where the electrons are spin-paired in three of the d orbitals and unpaired in two of the d orbitals.

The orbital contribution to the magnetic moment arises due to the motion of the unpaired electrons in the magnetic field. In [Co(H2O)6]2+, the unpaired electrons occupy the dxy and dxz orbitals, which are perpendicular to the external magnetic field. The motion of these electrons in the magnetic field results in an orbital contribution to the magnetic moment.

Therefore, [Co(H2O)6]2+ shows orbital contribution to the magnetic moment.

Answer: c)[Co(H2O)6]2
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Community Answer
The complex that shows orbital contribution to the magnetic moment, is...
Conditions for orbital contribution is:  1). Shape same, 2). Energy same, 3). Unsymmetrical filling of orbital. 
Option c)  follows these all conditions, so it has orbital contribution. 
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The complex that shows orbital contribution to the magnetic moment, isa)[Cu(H2O)6]2+b)[Ni(H2O)6]2+c)[Co(H2O)6]2+d)[Cr(H2O)6]2+Correct answer is option 'C'. Can you explain this answer?
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