Solution for Maths Sample Paper

Question 1:
Find the value of x in the following equation: 2x + 5 = 17.

Solution:
To find the value of x, we need to isolate it on one side of the equation.

Step 1: Subtract 5 from both sides of the equation:
2x + 5 - 5 = 17 - 5
2x = 12

Step 2: Divide both sides of the equation by 2:
2x/2 = 12/2
x = 6

Therefore, the value of x is 6.

Question 2:
Simplify the expression: 3(x + 2) - 4(2x - 1).

Solution:
To simplify the expression, we need to apply the distributive property and combine like terms.

Step 1: Distribute the coefficients to the terms inside the parentheses:
3(x) + 3(2) - 4(2x) + 4(1)

Step 2: Simplify each term:
3x + 6 - 8x + 4

Step 3: Combine like terms:
-5x + 10

Therefore, the simplified expression is -5x + 10.

Question 3:
Find the area of a rectangle with length 8 cm and width 5 cm.

Solution:
To find the area of a rectangle, we need to multiply its length by its width.

Step 1: Multiply the length and width:
Area = 8 cm x 5 cm
Area = 40 cm²

Therefore, the area of the rectangle is 40 cm².

Question 4:
Solve the equation for x: 4(3x - 2) = 20.

Solution:
To solve the equation, we need to isolate x on one side of the equation.

Step 1: Distribute the coefficient to the terms inside the parentheses:
12x - 8 = 20

Step 2: Add 8 to both sides of the equation:
12x - 8 + 8 = 20 + 8
12x = 28

Step 3: Divide both sides of the equation by 12:
12x/12 = 28/12
x = 7/3 or 2.33 (rounded to two decimal places)

Therefore, the value of x is 7/3 or approximately 2.33.

Question 5:
Find the perimeter of a square with a side length of 10 cm.

Solution:
To find the perimeter of a square, we need to multiply the length of one side by 4.

Step 1: Multiply the side length by 4:
Perimeter = 10 cm x 4
Perimeter = 40 cm

Therefore, the perimeter of the square is 40 cm.

U have sample Papers of which company ???