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CLAT Exam  >  CLAT Questions  >  A, B, C and D have got some money with them. ... Start Learning for Free
A, B, C and D have got some money with them. If A gives 8 rupees to B, B will have as much as C has and A will have 3 rupees less than what C has. Also if A takes 6 rupees from C, A will have twice as much money as D. If B and D together have 50 rupees, how much money does A and B have respectively ?  
  • a)
    29, 32
  • b)
    27, 40
  • c)
    32, 29
  • d)
    40, 27
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
A, B, C and D have got some money with them. If A gives 8 rupees to B,...
Given information:
- A gives 8 rupees to B, B will have as much as C has and A will have 3 rupees less than what C has.
- A takes 6 rupees from C, A will have twice as much money as D.
- B and D together have 50 rupees.

To find:
- How much money does A and B have respectively?

Solution:
Let us assume the initial amounts of A, B, C and D be a, b, c and d respectively.

According to the first condition,
- After A gives 8 rupees to B, B will have (b+8) rupees.
- And A will have (c-3) rupees.
- Therefore, c-3 = b+8
- Or, c-b = 11 (Equation 1)

According to the second condition,
- After A takes 6 rupees from C, A will have (a+6) rupees.
- And A will have twice as much money as D, i.e., a+6 = 2d
- Or, d = (a+6)/2 (Equation 2)

Given, B and D together have 50 rupees,
- b + d = 50
- Substituting the value of d from Equation 2,
- b + (a+6)/2 = 50
- Or, 2b + a + 6 = 100 (Equation 3)

Using Equations 1 and 3, we can solve for a and b.
- c-b = 11
- 2b + a + 6 = 100
- Substituting c-b = 11 in the second equation,
- 2b + a + 6 = 2(b+11) + 3
- Or, a = 22 - b

Substituting this value of a in Equation 3,
- 2b + (22-b) + 6 = 100
- Or, b = 27

Therefore, b = 27 and a = 40.
Hence, the answer is option D - 40, 27.
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Community Answer
A, B, C and D have got some money with them. If A gives 8 rupees to B,...
Let A has Rs.x , B has Rs.y
If A gives Rs.8 to B then
A has x-8 ,
B has y+8
and B becomes equal to C,
so let C has Rs.y+8.
Also A will have Rs 3 less than C ,
x-8 = y+8-3 => x - y = 13. -(1)

If A takes Rs.6 from C then
A will have x+6 ,
C will have y+8-6 = y+2
and A becomes twice of D , let D has Rs.z
So now , x+6=2z. -(2)
B+D = Rs.50 => y+z = 50. -(3)

From eq(2) , z = (x+6)/2. Putting this value of z in eq (3) , we get , y+(x+6)/2 = 50 => 2y+x+6 = 100 => 2y+x = 94. -(4)

On solving eq (1) & (4) , we get y = 27
then , x = 40.
Therefore A has Rs. 40 and B has Rs. 27
Correct option is d).
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A, B, C and D have got some money with them. If A gives 8 rupees to B, B will have as much as C has and A will have 3 rupees less than what C has. Also if A takes 6 rupees from C, A will have twice as much money as D. If B and D together have 50 rupees, how much money does A and B have respectively ? a)29, 32b)27, 40c)32, 29d)40, 27Correct answer is option 'D'. Can you explain this answer?
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