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The sum of a 2-digit no. and the no. obtained by reversing it's digits always divisible by A. 6 B. 4 C. 11 D. 10?
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The sum of a 2-digit no. and the no. obtained by reversing it's digits...
Let two digit number be ab and on reversing the number it will be …ba
their values in the number system are 10a+b and 10b+a
adding these two numbers = 10a+b + 10b+a = 11(a+b)
This 11(a+b) is a square number.
to make it a square number a+b should 11.
Hence, poosible values for a,b are (2,9), (3,8), (4,7), (5,6) ,,(9,2), (8,3), (7,4), (6,5)
finally 8 such numbers are there 29,38,47,56,92,83,74,65.
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The sum of a 2-digit no. and the no. obtained by reversing it's digits always divisible by A. 6 B. 4 C. 11 D. 10?
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