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If p(x) = x^4-x^2 x then find value of p(1/2) ?
Verified Answer
If p(x) = x^4-x^2 x then find value of p(1/2) ?
P(1/2)=(1/2)^4-(1/2)^2+1/2
p(1/2)=1/16-1/4+1/2=1-4+8/16=5/16
hence p(1/2)=5/16
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If p(x) = x^4-x^2 x then find value of p(1/2) ?
Problem:

If p(x) = x^4 - x^2x, find the value of p(1/2).

Solution:

To find the value of p(1/2), we substitute x = 1/2 into the given polynomial expression p(x) = x^4 - x^2x.

Step 1: Substitute x = 1/2 into the polynomial expression p(x) = x^4 - x^2x.

p(1/2) = (1/2)^4 - (1/2)^2(1/2)

Step 2: Simplify the expression.

p(1/2) = 1/16 - 1/4 * 1/2

Now, let's simplify further:


Step 3: Simplify the expression.

p(1/2) = 1/16 - 1/8

To subtract these fractions, we need to find a common denominator:


Step 4: Find the common denominator.

The common denominator for 16 and 8 is 16.

Step 5: Rewrite the fractions with the common denominator.

p(1/2) = 1/16 - 2/16

Step 6: Subtract the fractions.

p(1/2) = (1 - 2)/16

Now, we simplify the numerator:


Step 7: Simplify the numerator.

p(1/2) = -1/16

Therefore, the value of p(1/2) is -1/16.
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If p(x) = x^4-x^2 x then find value of p(1/2) ?
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If p(x) = x^4-x^2 x then find value of p(1/2) ?
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