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1H NMR spectrum of an organic compound recorded on a 500 MHz spectrometer showed a quartet with line positions at 1759, 1753, 1747, 1741 Hz. Chemical shift (s) and coupling constant (Hz) of the quartet are?           
  • a)
    3.5 ppm, 6Hz              
  • b)
    3.5 ppm, 12Hz               
  • c)
    3.6 ppm, 6Hz           
  • d)
    3.6 ppm, 12Hz
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
1H NMR spectrum of an organic compound recorded on a 500 MHz spectrome...
Explanation:
The quartet in the 1H NMR spectrum indicates that the proton in question is coupled to three neighboring protons. The line positions of the quartet are given as 1759, 1753, 1747, 1741 Hz. The chemical shift (s) and coupling constant (J) can be determined as follows:

Chemical shift (s):
The chemical shift is given by the frequency of the peak divided by the spectrometer frequency (in MHz). Therefore, the chemical shift can be calculated as follows:

s = (1759 + 1753 + 1747 + 1741) / 4 / 500
s = 3.5 ppm

Therefore, the chemical shift is 3.5 ppm.

Coupling constant (J):
The coupling constant is the distance between the peaks in the quartet. In this case, the distance is equal to the frequency difference between adjacent peaks, which is 6 Hz. Therefore, the coupling constant is 6 Hz.

Therefore, the correct answer is option A: 3.5 ppm, 6 Hz.
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Community Answer
1H NMR spectrum of an organic compound recorded on a 500 MHz spectrome...
1. To determine coupling constant:

check the difference between the peak in HZ
i.e, 1759, 1753 1747, 1741.

if u check all these numbers, the difference between them is 6. ie. 6HZ is the coupling constant.

2. To determine the chemical shift:

Add all the peak and divided by no. of peaks
i.e 1759+1753+1747+1741 / 4 = 1750HZ

now 1750HZ /500 MHZ
i.e, 1750HZ / 500 ×10*6HZ = 3.5×10*6HZ or 3.5ppm

therefore option A is right
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1H NMR spectrum of an organic compound recorded on a 500 MHz spectrometer showed a quartet with line positions at 1759, 1753, 1747, 1741 Hz. Chemical shift (s) and coupling constant (Hz) of the quartet are?a)3.5 ppm, 6Hzb)3.5 ppm, 12Hzc)3.6 ppm, 6Hzd)3.6 ppm, 12HzCorrect answer is option 'A'. Can you explain this answer?
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1H NMR spectrum of an organic compound recorded on a 500 MHz spectrometer showed a quartet with line positions at 1759, 1753, 1747, 1741 Hz. Chemical shift (s) and coupling constant (Hz) of the quartet are?a)3.5 ppm, 6Hzb)3.5 ppm, 12Hzc)3.6 ppm, 6Hzd)3.6 ppm, 12HzCorrect answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about 1H NMR spectrum of an organic compound recorded on a 500 MHz spectrometer showed a quartet with line positions at 1759, 1753, 1747, 1741 Hz. Chemical shift (s) and coupling constant (Hz) of the quartet are?a)3.5 ppm, 6Hzb)3.5 ppm, 12Hzc)3.6 ppm, 6Hzd)3.6 ppm, 12HzCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 1H NMR spectrum of an organic compound recorded on a 500 MHz spectrometer showed a quartet with line positions at 1759, 1753, 1747, 1741 Hz. Chemical shift (s) and coupling constant (Hz) of the quartet are?a)3.5 ppm, 6Hzb)3.5 ppm, 12Hzc)3.6 ppm, 6Hzd)3.6 ppm, 12HzCorrect answer is option 'A'. Can you explain this answer?.
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