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The ionic strength of a solution containing 0.008 M AlCl3 and 0.005 M KCl is:
(rounded up to two decimal places)
    Correct answer is between '0.050,0.055'. Can you explain this answer?
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    The ionic strength of a solution containing 0.008 M AlCl3 and 0.005 M ...
    Calculation of Ionic Strength

    Ionic strength is a measure of the total concentration of ions in a solution. It is calculated using the following formula:

    Ionic Strength = 1/2 Σci zi2

    Where,
    ci = the molar concentration of each ion in the solution
    zi = the charge of each ion

    Given Information

    The solution contains:
    - 0.008 M AlCl3
    - 0.005 M KCl

    The charges of each ion can be determined from their chemical formulas:
    - AlCl3 dissociates into Al3+ and 3Cl- ions
    - KCl dissociates into K+ and Cl- ions

    Therefore, the charges of each ion are:
    - Al3+ = 3+
    - Cl- = 1-
    - K+ = 1+

    Calculation

    Using the formula for ionic strength and the given information, we can calculate the ionic strength of the solution as follows:

    Ionic Strength = 1/2 [(0.008 M x (3+)2) + (0.008 M x 3 x 1-) + (0.005 M x (1+)2) + (0.005 M x 1 x 1-)]

    Ionic Strength = 1/2 [(0.072) + (0.024) + (0.005) + (0.005)]

    Ionic Strength = 0.053

    Therefore, the ionic strength of the solution containing 0.008 M AlCl3 and 0.005 M KCl is 0.053. Rounded up to two decimal places, the answer is between 0.050 and 0.055, as given in the question.
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    The ionic strength of a solution containing 0.008 M AlCl3 and 0.005 M KCl is:(rounded up to two decimal places)Correct answer is between '0.050,0.055'. Can you explain this answer?
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