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Ethylene glycol CH2OH—CH2OH is a common automobile antifreeze. It is water soluble and fairly non-volatile (b.p = 197°C). Calculate the freezing point (oC) of a solution containing 651 gm of thin substance in 2505 gm of water (rounded up to two decimal place):(Kf = 1.86 oC/m, Mol. Mass of ethylene glycol = 62 gm mole–1)Correct answer is between '-7.81,-7.78'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Ethylene glycol CH2OH—CH2OH is a common automobile antifreeze. It is water soluble and fairly non-volatile (b.p = 197°C). Calculate the freezing point (oC) of a solution containing 651 gm of thin substance in 2505 gm of water (rounded up to two decimal place):(Kf = 1.86 oC/m, Mol. Mass of ethylene glycol = 62 gm mole–1)Correct answer is between '-7.81,-7.78'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ethylene glycol CH2OH—CH2OH is a common automobile antifreeze. It is water soluble and fairly non-volatile (b.p = 197°C). Calculate the freezing point (oC) of a solution containing 651 gm of thin substance in 2505 gm of water (rounded up to two decimal place):(Kf = 1.86 oC/m, Mol. Mass of ethylene glycol = 62 gm mole–1)Correct answer is between '-7.81,-7.78'. Can you explain this answer?.

Solutions for Ethylene glycol CH2OH—CH2OH is a common automobile antifreeze. It is water soluble and fairly non-volatile (b.p = 197°C). Calculate the freezing point (oC) of a solution containing 651 gm of thin substance in 2505 gm of water (rounded up to two decimal place):(Kf = 1.86 oC/m, Mol. Mass of ethylene glycol = 62 gm mole–1)Correct answer is between '-7.81,-7.78'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry. Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.

Here you can find the meaning of Ethylene glycol CH2OH—CH2OH is a common automobile antifreeze. It is water soluble and fairly non-volatile (b.p = 197°C). Calculate the freezing point (oC) of a solution containing 651 gm of thin substance in 2505 gm of water (rounded up to two decimal place):(Kf = 1.86 oC/m, Mol. Mass of ethylene glycol = 62 gm mole–1)Correct answer is between '-7.81,-7.78'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Ethylene glycol CH2OH—CH2OH is a common automobile antifreeze. It is water soluble and fairly non-volatile (b.p = 197°C). Calculate the freezing point (oC) of a solution containing 651 gm of thin substance in 2505 gm of water (rounded up to two decimal place):(Kf = 1.86 oC/m, Mol. Mass of ethylene glycol = 62 gm mole–1)Correct answer is between '-7.81,-7.78'. Can you explain this answer?, a detailed solution for Ethylene glycol CH2OH—CH2OH is a common automobile antifreeze. It is water soluble and fairly non-volatile (b.p = 197°C). Calculate the freezing point (oC) of a solution containing 651 gm of thin substance in 2505 gm of water (rounded up to two decimal place):(Kf = 1.86 oC/m, Mol. Mass of ethylene glycol = 62 gm mole–1)Correct answer is between '-7.81,-7.78'. Can you explain this answer? has been provided alongside types of Ethylene glycol CH2OH—CH2OH is a common automobile antifreeze. It is water soluble and fairly non-volatile (b.p = 197°C). Calculate the freezing point (oC) of a solution containing 651 gm of thin substance in 2505 gm of water (rounded up to two decimal place):(Kf = 1.86 oC/m, Mol. Mass of ethylene glycol = 62 gm mole–1)Correct answer is between '-7.81,-7.78'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Ethylene glycol CH2OH—CH2OH is a common automobile antifreeze. It is water soluble and fairly non-volatile (b.p = 197°C). Calculate the freezing point (oC) of a solution containing 651 gm of thin substance in 2505 gm of water (rounded up to two decimal place):(Kf = 1.86 oC/m, Mol. Mass of ethylene glycol = 62 gm mole–1)Correct answer is between '-7.81,-7.78'. Can you explain this answer? tests, examples and also practice Chemistry tests.