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Two semiconductor material have exactly the same properties except that material A has a bandgap of 1.0eV and material B has a bandgap energy of 1.2 eV. The ratio of intrinsic concentration of material A to that ofmaterial B is
- a)2016
- b)47.5
- c)58.23
- d)1048
Correct answer is option 'B'. Can you explain this answer?
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Two semiconductor material have exactly the same properties except tha...
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Calculation of Ratio of Intrinsic Concentration:
Intrinsic carrier concentration of a semiconductor material is given by the equation:
ni = A * T^(3/2) * exp(-Eg / (2 * k * T))
where:
ni = intrinsic carrier concentration
A = constant
T = temperature
Eg = bandgap energy
k = Boltzmann constant
Given:
EgA = 1.0 eV
EgB = 1.2 eV
Calculating the Ratio:
Since material A and material B have the same properties except for the bandgap energy, we can write:
niA / niB = (A * T^(3/2) * exp(-EgA / (2 * k * T))) / (A * T^(3/2) * exp(-EgB / (2 * k * T))
Canceling out the constants A and T^(3/2), we get:
niA / niB = exp((EgB - EgA) / (2 * k * T))
Substitute the values of EgA, EgB, and k, we get:
niA / niB = exp((1.2 - 1.0) / (2 * 8.617 x 10^(-5) * T))
niA / niB = exp(0.2 / (1.7234 x 10^(-4) * T))
niA / niB = exp(1161.04 / T)
Conclusion:
The ratio of intrinsic concentration of material A to material B is dependent on the temperature T. The given options do not provide the temperature value, so the ratio cannot be calculated accurately. However, the correct approach to solve this problem is outlined above.
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Two semiconductor material have exactly the same properties except that material A has a bandgap of 1.0eV and material B has a bandgap energy of 1.2 eV. The ratio of intrinsic concentration of material A to that ofmaterial B isa)2016b)47.5c)58.23d)1048Correct answer is option 'B'. Can you explain this answer?
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