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Standard entropies of X2, Y2 and XY3 are given below the reaction
Q. At what temperature, reaction would be in equilibrium? 
  • a)
    500 K
  • b)
    750 K
  • c)
    1000 K
  • d)
    1250 K
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Standard entropies of X2, Y2 and XY3 are given below the reactionQ. At...
1/2X + 3/2Y2 ⟶XY3,
ΔH= −30 kJ
ΔSreaction = ∑ΔSproduct−∑ΔSreactant 
X+ 3Y→ 2XY3
​ΔH=−60 kJ
ΔSreaction = 2×50−3×40−1×60 =100−120−60=−80 JK−1mol−1
 ΔG=ΔH−TΔS=0
ΔH=TΔS
1000×(−60)=−80×T
T=750 K
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Most Upvoted Answer
Standard entropies of X2, Y2 and XY3 are given below the reactionQ. At...
1/2X + 3/2Y2 ⟶XY3,
ΔH= −30 kJ
ΔSreaction = ∑ΔSproduct−∑ΔSreactant 
X+ 3Y→ 2XY3
​ΔH=−60 kJ
ΔSreaction = 2×50−3×40−1×60 =100−120−60=−80 JK−1mol−1
 ΔG=ΔH−TΔS=0
ΔH=TΔS
1000×(−60)=−80×T
T=750 K
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Standard entropies of X2, Y2 and XY3 are given below the reactionQ. At...
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