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For the reaction, at 1000° CΔG° = - 24 kJ mol-1, = 0.0030 atm.Q. Hence, ΔG at this temperature isa)- 60.5 kJ mol-1b)- 85.49 kJ mol-1c)-33.5 kJ mol-1d)+ 33.5 kJ mol-1Correct answer is option 'B'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about For the reaction, at 1000° CΔG° = - 24 kJ mol-1, = 0.0030 atm.Q. Hence, ΔG at this temperature isa)- 60.5 kJ mol-1b)- 85.49 kJ mol-1c)-33.5 kJ mol-1d)+ 33.5 kJ mol-1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the reaction, at 1000° CΔG° = - 24 kJ mol-1, = 0.0030 atm.Q. Hence, ΔG at this temperature isa)- 60.5 kJ mol-1b)- 85.49 kJ mol-1c)-33.5 kJ mol-1d)+ 33.5 kJ mol-1Correct answer is option 'B'. Can you explain this answer?.

Solutions for For the reaction, at 1000° CΔG° = - 24 kJ mol-1, = 0.0030 atm.Q. Hence, ΔG at this temperature isa)- 60.5 kJ mol-1b)- 85.49 kJ mol-1c)-33.5 kJ mol-1d)+ 33.5 kJ mol-1Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.

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