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2000 cc of air takes 1.6 minutes to pass through a standard specimen of sand (5.08 cm high and 5.08 cm in diameter). The manometer indicates pressure as 5 g/cm2. The permeability number is
Correct answer is between '62,63'. Can you explain this answer?
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2000 cc of air takes 1.6 minutes to pass through a standard specimen o...
Calculation of Permeability Number
Given data:
- Volume of air = 2000 cc
- Time taken = 1.6 minutes
- Height of specimen = 5.08 cm
- Diameter of specimen = 5.08 cm
- Manometer pressure = 5 g/cm2
1. Calculation of Flow Rate
- Convert volume of air to liters: 2000 cc = 2 L
- Convert time to seconds: 1.6 minutes = 96 seconds
- Flow rate = volume / time = 2 L / 96 s = 0.0208 L/s
2. Calculation of Cross-Sectional Area
- Diameter = 5.08 cm
- Radius = diameter / 2 = 2.54 cm
- Cross-sectional area = πr2 = 20.21 cm2
3. Calculation of Velocity
- Velocity = flow rate / cross-sectional area = 0.0208 L/s / 20.21 cm2 = 0.001 L/s/cm2
- Convert to m/s: 0.001 L/s/cm2 = 0.000001 m3/s/m2 = 0.000001 m/s
4. Calculation of Permeability Number
- Permeability number = (velocity x height x density) / (viscosity x pressure)
- Density of air at standard conditions = 1.2 kg/m3
- Viscosity of air at standard conditions = 1.8 x 10-5 Pa.s
- Permeability number = (0.000001 m/s x 0.0508 m x 1.2 kg/m3) / (1.8 x 10-5 Pa.s x 5 g/cm2 x 980 cm/s2)
- Permeability number = 62.4
Therefore, the permeability number of the sand specimen is 62.4.
Given data:
- Volume of air = 2000 cc
- Time taken = 1.6 minutes
- Height of specimen = 5.08 cm
- Diameter of specimen = 5.08 cm
- Manometer pressure = 5 g/cm2
1. Calculation of Flow Rate
- Convert volume of air to liters: 2000 cc = 2 L
- Convert time to seconds: 1.6 minutes = 96 seconds
- Flow rate = volume / time = 2 L / 96 s = 0.0208 L/s
2. Calculation of Cross-Sectional Area
- Diameter = 5.08 cm
- Radius = diameter / 2 = 2.54 cm
- Cross-sectional area = πr2 = 20.21 cm2
3. Calculation of Velocity
- Velocity = flow rate / cross-sectional area = 0.0208 L/s / 20.21 cm2 = 0.001 L/s/cm2
- Convert to m/s: 0.001 L/s/cm2 = 0.000001 m3/s/m2 = 0.000001 m/s
4. Calculation of Permeability Number
- Permeability number = (velocity x height x density) / (viscosity x pressure)
- Density of air at standard conditions = 1.2 kg/m3
- Viscosity of air at standard conditions = 1.8 x 10-5 Pa.s
- Permeability number = (0.000001 m/s x 0.0508 m x 1.2 kg/m3) / (1.8 x 10-5 Pa.s x 5 g/cm2 x 980 cm/s2)
- Permeability number = 62.4
Therefore, the permeability number of the sand specimen is 62.4.
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2000 cc of air takes 1.6 minutes to pass through a standard specimen of sand (5.08 cm high and 5.08 cm in diameter). The manometer indicates pressure as 5 g/cm2. The permeability number isCorrect answer is between '62,63'. Can you explain this answer?
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2000 cc of air takes 1.6 minutes to pass through a standard specimen of sand (5.08 cm high and 5.08 cm in diameter). The manometer indicates pressure as 5 g/cm2. The permeability number isCorrect answer is between '62,63'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about 2000 cc of air takes 1.6 minutes to pass through a standard specimen of sand (5.08 cm high and 5.08 cm in diameter). The manometer indicates pressure as 5 g/cm2. The permeability number isCorrect answer is between '62,63'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2000 cc of air takes 1.6 minutes to pass through a standard specimen of sand (5.08 cm high and 5.08 cm in diameter). The manometer indicates pressure as 5 g/cm2. The permeability number isCorrect answer is between '62,63'. Can you explain this answer?.
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