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The correct statement(s) regarding the isomers of compound N-ethyl-N-methyl-l-propanamine is/are
- a)A pair of enantiomers remain in dynamic equilibrium
- b)Addition of HCI results in the formation of enantiomeric hydrochloride salts
- c)Addition of a pure enantiomer of 2-methyl butanoic acid to the solution of amine results in formation of a pair of diastereomeric salts
- d)Its enantiomers can be separated by gas chromatography
Correct answer is option 'A,B,C'. Can you explain this answer?
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The correct statement(s) regarding the isomers of compound N-ethyl-N-m...
Isomers of compound N-ethyl-N-methyl-l-propanamine
The compound N-ethyl-N-methyl-l-propanamine is a chiral compound, meaning it has a chiral center and can exist as different stereoisomers. In this case, there are two possible isomers: the R-isomer and the S-isomer.
Pair of enantiomers remain in dynamic equilibrium
Enantiomers are non-superimposable mirror images of each other. In the case of N-ethyl-N-methyl-l-propanamine, the R-isomer and the S-isomer are enantiomers. When enantiomers are in a solution, they can interconvert through a process called enantiomerization. This means that the R-isomer can convert to the S-isomer and vice versa. Therefore, a pair of enantiomers remains in dynamic equilibrium.
Addition of HCI results in the formation of enantiomeric hydrochloride salts
When N-ethyl-N-methyl-l-propanamine reacts with hydrochloric acid (HCI), it forms a salt known as N-ethyl-N-methyl-l-propanamine hydrochloride. Since the compound has a chiral center, the reaction with HCI results in the formation of enantiomeric hydrochloride salts. The R-isomer reacts to form the R-enantiomer hydrochloride salt, and the S-isomer reacts to form the S-enantiomer hydrochloride salt.
Addition of a pure enantiomer of 2-methyl butanoic acid to the solution of amine results in the formation of a pair of diastereomeric salts
When a pure enantiomer of 2-methyl butanoic acid is added to the solution of N-ethyl-N-methyl-l-propanamine, a reaction occurs between the acid and the amine. Since the acid and the amine have different stereochemistry, the reaction results in the formation of diastereomeric salts. Diastereomers are stereoisomers that are not mirror images of each other and have different chemical properties.
Enantiomers can be separated by gas chromatography
Gas chromatography is a technique used to separate and analyze compounds in a mixture. It works based on the differences in the physical properties of the compounds, such as boiling points or polarity. Since enantiomers have the same physical properties, they cannot be separated by regular gas chromatography. However, specialized techniques such as chiral gas chromatography can be used to separate enantiomers based on their different interactions with a chiral stationary phase.
Therefore, the correct statements regarding the isomers of compound N-ethyl-N-methyl-l-propanamine are A) A pair of enantiomers remain in dynamic equilibrium, B) Addition of HCI results in the formation of enantiomeric hydrochloride salts, and C) Addition of a pure enantiomer of 2-methyl butanoic acid to the solution of amine results in the formation of a pair of diastereomeric salts.
The compound N-ethyl-N-methyl-l-propanamine is a chiral compound, meaning it has a chiral center and can exist as different stereoisomers. In this case, there are two possible isomers: the R-isomer and the S-isomer.
Pair of enantiomers remain in dynamic equilibrium
Enantiomers are non-superimposable mirror images of each other. In the case of N-ethyl-N-methyl-l-propanamine, the R-isomer and the S-isomer are enantiomers. When enantiomers are in a solution, they can interconvert through a process called enantiomerization. This means that the R-isomer can convert to the S-isomer and vice versa. Therefore, a pair of enantiomers remains in dynamic equilibrium.
Addition of HCI results in the formation of enantiomeric hydrochloride salts
When N-ethyl-N-methyl-l-propanamine reacts with hydrochloric acid (HCI), it forms a salt known as N-ethyl-N-methyl-l-propanamine hydrochloride. Since the compound has a chiral center, the reaction with HCI results in the formation of enantiomeric hydrochloride salts. The R-isomer reacts to form the R-enantiomer hydrochloride salt, and the S-isomer reacts to form the S-enantiomer hydrochloride salt.
Addition of a pure enantiomer of 2-methyl butanoic acid to the solution of amine results in the formation of a pair of diastereomeric salts
When a pure enantiomer of 2-methyl butanoic acid is added to the solution of N-ethyl-N-methyl-l-propanamine, a reaction occurs between the acid and the amine. Since the acid and the amine have different stereochemistry, the reaction results in the formation of diastereomeric salts. Diastereomers are stereoisomers that are not mirror images of each other and have different chemical properties.
Enantiomers can be separated by gas chromatography
Gas chromatography is a technique used to separate and analyze compounds in a mixture. It works based on the differences in the physical properties of the compounds, such as boiling points or polarity. Since enantiomers have the same physical properties, they cannot be separated by regular gas chromatography. However, specialized techniques such as chiral gas chromatography can be used to separate enantiomers based on their different interactions with a chiral stationary phase.
Therefore, the correct statements regarding the isomers of compound N-ethyl-N-methyl-l-propanamine are A) A pair of enantiomers remain in dynamic equilibrium, B) Addition of HCI results in the formation of enantiomeric hydrochloride salts, and C) Addition of a pure enantiomer of 2-methyl butanoic acid to the solution of amine results in the formation of a pair of diastereomeric salts.
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The correct statement(s) regarding the isomers of compound N-ethyl-N-m...
correct options are a, b and c
A pair of enantiomers remain in dynamic equilibrium.Addition of HI results in the formation of enantiomeric hydrochloride salts. This statement is correct because when N-ethyl-N-methyl-l-propanamine reacts with hydroiodic acid (HI), enantiomeric hydrochloride salts are formed. Addition of a pure enantiomer of 2-methyl butanoic acid to the solution of amine results in the formation of a pair of diastereomeric salts. This statement is also correct. When a pure enantiomer of 2-methyl butanoic acid is added to the solution of the amine, it forms diastereomeric salts
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The correct statement(s) regarding the isomers of compound N-ethyl-N-methyl-l-propanamine is/area)A pair of enantiomers remain in dynamic equilibriumb)Addition of HCI results in the formation of enantiomeric hydrochloride saltsc)Addition of a pure enantiomer of 2-methyl butanoic acid to the solution of amine results in formation of a pair of diastereomeric saltsd)Its enantiomers can be separated by gas chromatographyCorrect answer is option 'A,B,C'. Can you explain this answer?
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The correct statement(s) regarding the isomers of compound N-ethyl-N-methyl-l-propanamine is/area)A pair of enantiomers remain in dynamic equilibriumb)Addition of HCI results in the formation of enantiomeric hydrochloride saltsc)Addition of a pure enantiomer of 2-methyl butanoic acid to the solution of amine results in formation of a pair of diastereomeric saltsd)Its enantiomers can be separated by gas chromatographyCorrect answer is option 'A,B,C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The correct statement(s) regarding the isomers of compound N-ethyl-N-methyl-l-propanamine is/area)A pair of enantiomers remain in dynamic equilibriumb)Addition of HCI results in the formation of enantiomeric hydrochloride saltsc)Addition of a pure enantiomer of 2-methyl butanoic acid to the solution of amine results in formation of a pair of diastereomeric saltsd)Its enantiomers can be separated by gas chromatographyCorrect answer is option 'A,B,C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The correct statement(s) regarding the isomers of compound N-ethyl-N-methyl-l-propanamine is/area)A pair of enantiomers remain in dynamic equilibriumb)Addition of HCI results in the formation of enantiomeric hydrochloride saltsc)Addition of a pure enantiomer of 2-methyl butanoic acid to the solution of amine results in formation of a pair of diastereomeric saltsd)Its enantiomers can be separated by gas chromatographyCorrect answer is option 'A,B,C'. Can you explain this answer?.
The correct statement(s) regarding the isomers of compound N-ethyl-N-methyl-l-propanamine is/area)A pair of enantiomers remain in dynamic equilibriumb)Addition of HCI results in the formation of enantiomeric hydrochloride saltsc)Addition of a pure enantiomer of 2-methyl butanoic acid to the solution of amine results in formation of a pair of diastereomeric saltsd)Its enantiomers can be separated by gas chromatographyCorrect answer is option 'A,B,C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The correct statement(s) regarding the isomers of compound N-ethyl-N-methyl-l-propanamine is/area)A pair of enantiomers remain in dynamic equilibriumb)Addition of HCI results in the formation of enantiomeric hydrochloride saltsc)Addition of a pure enantiomer of 2-methyl butanoic acid to the solution of amine results in formation of a pair of diastereomeric saltsd)Its enantiomers can be separated by gas chromatographyCorrect answer is option 'A,B,C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The correct statement(s) regarding the isomers of compound N-ethyl-N-methyl-l-propanamine is/area)A pair of enantiomers remain in dynamic equilibriumb)Addition of HCI results in the formation of enantiomeric hydrochloride saltsc)Addition of a pure enantiomer of 2-methyl butanoic acid to the solution of amine results in formation of a pair of diastereomeric saltsd)Its enantiomers can be separated by gas chromatographyCorrect answer is option 'A,B,C'. Can you explain this answer?.
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ample number of questions to practice The correct statement(s) regarding the isomers of compound N-ethyl-N-methyl-l-propanamine is/area)A pair of enantiomers remain in dynamic equilibriumb)Addition of HCI results in the formation of enantiomeric hydrochloride saltsc)Addition of a pure enantiomer of 2-methyl butanoic acid to the solution of amine results in formation of a pair of diastereomeric saltsd)Its enantiomers can be separated by gas chromatographyCorrect answer is option 'A,B,C'. Can you explain this answer? tests, examples and also practice Class 11 tests.
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