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If trans-2-pentene is treated with Br2 in CCI4 in presence of Lewis acid FeBr3
  • a)
    a pair of enantiomers of 2, 3-dibromopentane, but in unequal amounts are formed
  • b)
    a racemic mixture of 2, 3-dibromopentane is formed
  • c)
    a pure enantiomer of 2, 3-dibromopentane is formed
  • d)
    a pair of diastereomers of 2, 3 dibromopentane is formed
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If trans-2-pentene is treated with Br2 in CCI4 in presence of Lewis ac...
Trans-2-pentene on reaction with Br2 in CCl4 produces mainly (±) 2,3dibromopentene. A molecule of bromine is added across C=C double bond. A racemic mixture is obtained as the product.
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If trans-2-pentene is treated with Br2 in CCI4 in presence of Lewis ac...
Treatment of Trans-2-Pentene with Br2 in CCI4 in the Presence of Lewis Acid FeBr3

Formation of 2,3-dibromopentane

When trans-2-pentene is treated with Br2 in CCI4 in the presence of Lewis acid FeBr3, the double bond of the alkene is broken and two molecules of Br2 add to the carbon atoms of the double bond. This results in the formation of 2,3-dibromopentane.

Possible Stereoisomers

The addition of Br2 to the double bond of trans-2-pentene results in the formation of two possible stereoisomers of 2,3-dibromopentane. These are:

- Enantiomers: Two molecules that are mirror images of each other but cannot be superimposed. They have opposite configurations at every chiral center.
- Diastereomers: Two molecules that are not mirror images of each other but have different configurations at one or more chiral centers.

Formation of Racemic Mixture

In the given reaction, a racemic mixture of 2,3-dibromopentane is formed. This means that equal amounts of both enantiomers are formed. Since trans-2-pentene does not have any chiral centers, the enantiomers are formed due to the presence of the two carbon atoms that were part of the double bond.

Conclusion

When trans-2-pentene is treated with Br2 in CCI4 in the presence of Lewis acid FeBr3, a racemic mixture of 2,3-dibromopentane is formed.
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If trans-2-pentene is treated with Br2 in CCI4 in presence of Lewis acid FeBr3a)a pair of enantiomers of 2, 3-dibromopentane, but in unequal amounts are formedb)a racemic mixture of 2, 3-dibromopentane is formedc)a pure enantiomer of 2, 3-dibromopentane is formedd)a pair of diastereomers of 2, 3 dibromopentane is formedCorrect answer is option 'B'. Can you explain this answer?
Question Description
If trans-2-pentene is treated with Br2 in CCI4 in presence of Lewis acid FeBr3a)a pair of enantiomers of 2, 3-dibromopentane, but in unequal amounts are formedb)a racemic mixture of 2, 3-dibromopentane is formedc)a pure enantiomer of 2, 3-dibromopentane is formedd)a pair of diastereomers of 2, 3 dibromopentane is formedCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about If trans-2-pentene is treated with Br2 in CCI4 in presence of Lewis acid FeBr3a)a pair of enantiomers of 2, 3-dibromopentane, but in unequal amounts are formedb)a racemic mixture of 2, 3-dibromopentane is formedc)a pure enantiomer of 2, 3-dibromopentane is formedd)a pair of diastereomers of 2, 3 dibromopentane is formedCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If trans-2-pentene is treated with Br2 in CCI4 in presence of Lewis acid FeBr3a)a pair of enantiomers of 2, 3-dibromopentane, but in unequal amounts are formedb)a racemic mixture of 2, 3-dibromopentane is formedc)a pure enantiomer of 2, 3-dibromopentane is formedd)a pair of diastereomers of 2, 3 dibromopentane is formedCorrect answer is option 'B'. Can you explain this answer?.
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