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A compound when treated with sodium peroxide and the solution is boiled with nitric acid and then treated with ammonium molybdate is the test for:
  • a)
    Nitrogen
  • b)
    Phosphorus
  • c)
    Sulphur
  • d)
    Halogen
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A compound when treated with sodium peroxide and the solution is boile...
The phosphorus containing organic compound are detected by 'Lassaigne's test' by heated with an oxidizing agent (sodium peroxide)
The phosphorus present in the compound in oxidised to phosphate.
The solution is boiled with nitric acid and then treated with ammonium molybdate to produced canary yellow precipitate.
Na3PO4 + 3HNO3 ⟶ H3PO4 + 3NaNO3 
H3PO4 + 12(NH4)2MoO4 (Ammonium molybdate) + 21HNO3⟶(NH4)3PO4⋅12MoO3↓ + 21NH4NO3 + 12H2O
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Most Upvoted Answer
A compound when treated with sodium peroxide and the solution is boile...
Test for Phosphorus

When a compound is treated with sodium peroxide and the resulting solution is boiled with nitric acid, the phosphorus present in the compound is converted into phosphoric acid. The phosphoric acid formed in the solution reacts with ammonium molybdate to form a yellow precipitate of ammonium phosphomolybdate. This is a confirmatory test for the presence of phosphorus in the given compound.

Procedure

The following steps are involved in the test for phosphorus:

1. Treatment with sodium peroxide: The given compound is treated with sodium peroxide. This leads to the formation of alkaline solution, which helps in the conversion of phosphorus into phosphoric acid.

2. Boiling with nitric acid: The alkaline solution obtained in step 1 is boiled with nitric acid. This leads to the conversion of phosphorus into phosphoric acid.

3. Treatment with ammonium molybdate: After boiling with nitric acid, the resulting solution is treated with ammonium molybdate. This leads to the formation of yellow precipitate of ammonium phosphomolybdate.

4. Confirmation of the test: The formation of yellow precipitate confirms the presence of phosphorus in the given compound.

Conclusion

Thus, the test for phosphorus involves the treatment of the compound with sodium peroxide, boiling with nitric acid, and treatment with ammonium molybdate to form a yellow precipitate of ammonium phosphomolybdate, which confirms the presence of phosphorus in the compound.
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A compound when treated with sodium peroxide and the solution is boiled with nitric acid and then treated with ammonium molybdate is the test for:a)Nitrogenb)Phosphorusc)Sulphurd)HalogenCorrect answer is option 'B'. Can you explain this answer?
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