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The white precipitate which is formed in the detection of chloride ion is due to the formation of:
- a)Ammonium chloride
- b)Sodium chloride
- c)Aluminium sulphate
- d)Calcium chloride
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The white precipitate which is formed in the detection of chloride ion...
AgCl is a precipitate. So, if a silver nitrate solution is added to a sample of the being tested solution, a white ppt. is obtained. This precipitated Agcl is soluble in an excess of Ammonium Hydroxide soltion because of the formation of [Ag(NH3)2]+ complex ions.
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The white precipitate which is formed in the detection of chloride ion...
Understanding Chloride Ion Detection
When testing for chloride ions (Cl⁻), a white precipitate is formed, which is primarily due to the reaction with silver nitrate (AgNO₃) in the presence of an ammonium solution. This results in the formation of silver chloride (AgCl), a white solid.
Key Points of the Reaction
- Reaction with Silver Nitrate:
When chloride ions are introduced to a solution containing silver nitrate, the following reaction occurs:
AgNO₃ + Cl⁻ → AgCl (s) + NO₃⁻
- Formation of White Precipitate:
The silver chloride precipitate appears as a white solid, indicating the presence of chloride ions in the sample.
Why Option 'A' (Ammonium Chloride) is Incorrect
- Misinterpretation of Precipitate:
While ammonium chloride (NH₄Cl) is a soluble salt, it does not form a white precipitate in this testing procedure. The confusion may arise since ammonium ions can be present in the solution.
- Correct Precipitate:
The white precipitate specifically refers to silver chloride, not ammonium chloride. Therefore, option 'A' is misleading in this context.
Conclusion
In conclusion, the formation of the white precipitate during the detection of chloride ions is primarily due to the reaction with silver nitrate, resulting in silver chloride, not ammonium chloride. Understanding this distinction is crucial for accurate identification of ions in chemical analysis.
When testing for chloride ions (Cl⁻), a white precipitate is formed, which is primarily due to the reaction with silver nitrate (AgNO₃) in the presence of an ammonium solution. This results in the formation of silver chloride (AgCl), a white solid.
Key Points of the Reaction
- Reaction with Silver Nitrate:
When chloride ions are introduced to a solution containing silver nitrate, the following reaction occurs:
AgNO₃ + Cl⁻ → AgCl (s) + NO₃⁻
- Formation of White Precipitate:
The silver chloride precipitate appears as a white solid, indicating the presence of chloride ions in the sample.
Why Option 'A' (Ammonium Chloride) is Incorrect
- Misinterpretation of Precipitate:
While ammonium chloride (NH₄Cl) is a soluble salt, it does not form a white precipitate in this testing procedure. The confusion may arise since ammonium ions can be present in the solution.
- Correct Precipitate:
The white precipitate specifically refers to silver chloride, not ammonium chloride. Therefore, option 'A' is misleading in this context.
Conclusion
In conclusion, the formation of the white precipitate during the detection of chloride ions is primarily due to the reaction with silver nitrate, resulting in silver chloride, not ammonium chloride. Understanding this distinction is crucial for accurate identification of ions in chemical analysis.
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Community Answer
The white precipitate which is formed in the detection of chloride ion...
Answer is AgCl
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