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How many different alkyne isomers upon hydrogenation in the presence of CaCO3 / Pd gives 4-methyl hexene which is simultaneously c/s at double bond?
Correct answer is '2'. Can you explain this answer?
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How many different alkyne isomers upon hydrogenation in the presence o...
Solution:
Given: Hydrogenation of alkyne in the presence of CaCO3 / Pd gives 4-methyl hexene which is simultaneously cis/trans at double bond.
To find: Number of different alkyne isomers.
Step 1: Write the formula of 4-methyl hexene.
4-methyl hexene formula: CH3-CH2-CH=CH-CH2-CH3
Step 2: Draw the structural formula of 4-methyl hexene.
H H
│ │
H-C-C-C=C-C-H
│ │
H CH3
Step 3: Identify the position of the double bond.
Double bond is present between 3rd and 4th carbon atoms.
Step 4: Identify the alkynes which can give 4-methyl hexene upon hydrogenation in the presence of CaCO3 / Pd.
There are 2 possible alkyne isomers which can give 4-methyl hexene upon hydrogenation in the presence of CaCO3 / Pd.
- 3-methyl-1-pentene - This alkyne can give 4-methyl hexene upon hydrogenation in the presence of CaCO3 / Pd. The double bond is present between 2nd and 3rd carbon atoms. On hydrogenation, the double bond is converted into a single bond and a methyl group is added to the 3rd carbon atom.
- 2-methyl-2-pentene - This alkyne can also give 4-methyl hexene upon hydrogenation in the presence of CaCO3 / Pd. The double bond is present between 2nd and 3rd carbon atoms. On hydrogenation, the double bond is converted into a single bond and a methyl group is added to the 4th carbon atom.
Both of these alkyne isomers give 4-methyl hexene which is simultaneously cis/trans at double bond.
Therefore, the correct answer is '2'.
Given: Hydrogenation of alkyne in the presence of CaCO3 / Pd gives 4-methyl hexene which is simultaneously cis/trans at double bond.
To find: Number of different alkyne isomers.
Step 1: Write the formula of 4-methyl hexene.
4-methyl hexene formula: CH3-CH2-CH=CH-CH2-CH3
Step 2: Draw the structural formula of 4-methyl hexene.
H H
│ │
H-C-C-C=C-C-H
│ │
H CH3
Step 3: Identify the position of the double bond.
Double bond is present between 3rd and 4th carbon atoms.
Step 4: Identify the alkynes which can give 4-methyl hexene upon hydrogenation in the presence of CaCO3 / Pd.
There are 2 possible alkyne isomers which can give 4-methyl hexene upon hydrogenation in the presence of CaCO3 / Pd.
- 3-methyl-1-pentene - This alkyne can give 4-methyl hexene upon hydrogenation in the presence of CaCO3 / Pd. The double bond is present between 2nd and 3rd carbon atoms. On hydrogenation, the double bond is converted into a single bond and a methyl group is added to the 3rd carbon atom.
- 2-methyl-2-pentene - This alkyne can also give 4-methyl hexene upon hydrogenation in the presence of CaCO3 / Pd. The double bond is present between 2nd and 3rd carbon atoms. On hydrogenation, the double bond is converted into a single bond and a methyl group is added to the 4th carbon atom.
Both of these alkyne isomers give 4-methyl hexene which is simultaneously cis/trans at double bond.
Therefore, the correct answer is '2'.
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Community Answer
How many different alkyne isomers upon hydrogenation in the presence o...
Yes cis when both side left and right side double bond same thing same side
So ch3-c ///c-cch2ch3
where this /// denotes triple bond
here h h on same side on hydrogenation
ch3ch2ch2cch3///chch3
where /// is triple bond here ch 3 ch 3 on same side
it is not EZ configuration but cis trans Bhai
So ch3-c ///c-cch2ch3
where this /// denotes triple bond
here h h on same side on hydrogenation
ch3ch2ch2cch3///chch3
where /// is triple bond here ch 3 ch 3 on same side
it is not EZ configuration but cis trans Bhai
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How many different alkyne isomers upon hydrogenation in the presence of CaCO3 / Pd gives 4-methyl hexene which is simultaneously c/s at double bond?Correct answer is '2'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about How many different alkyne isomers upon hydrogenation in the presence of CaCO3 / Pd gives 4-methyl hexene which is simultaneously c/s at double bond?Correct answer is '2'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How many different alkyne isomers upon hydrogenation in the presence of CaCO3 / Pd gives 4-methyl hexene which is simultaneously c/s at double bond?Correct answer is '2'. Can you explain this answer?.
How many different alkyne isomers upon hydrogenation in the presence of CaCO3 / Pd gives 4-methyl hexene which is simultaneously c/s at double bond?Correct answer is '2'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about How many different alkyne isomers upon hydrogenation in the presence of CaCO3 / Pd gives 4-methyl hexene which is simultaneously c/s at double bond?Correct answer is '2'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How many different alkyne isomers upon hydrogenation in the presence of CaCO3 / Pd gives 4-methyl hexene which is simultaneously c/s at double bond?Correct answer is '2'. Can you explain this answer?.
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