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A cylinderical vessel contains 49.896 litres of liquid. cost of painting its CSA at 2 paise/sq cm is Rs. 95.04.
Then its total surface area is ______.
  • a)
    5724 cm2
  • b)
    7524 cm2
  • c)
    5742 cm2
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?
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Question:
Find the total surface area of a cylindrical vessel that contains 49.896 litres of liquid and the cost of painting its CSA at 2 paise/sq cm is Rs. 95.04.

Solution:
Let the radius of the cylindrical vessel be r and the height be h.

Volume of the cylindrical vessel = πr²h = 49.896 litres = 49896 cm³

Now, we know that the cost of painting its CSA at 2 paise/sq cm is Rs. 95.04.
Let the total surface area of the cylindrical vessel be A.

Cost of painting = 2paise/sq cm = Rs. 0.02/sq cm
Cost of painting the entire surface area = Rs. 95.04

Therefore, we have:

Rs. 0.02/sq cm x A = Rs. 95.04

A = 95.04/0.02 = 4752 sq cm

Now, the total surface area of the cylindrical vessel is given by:

Total surface area = 2πrh + 2πr²

We can solve for h using the volume of the cylindrical vessel:

πr²h = 49896

h = 49896/πr²

Substituting this value of h in the expression for total surface area, we get:

Total surface area = 2πr(49896/πr²) + 2πr²

Total surface area = 2(49896/r) + 2πr²

To find the value of r that minimizes the surface area, we differentiate the expression for surface area with respect to r:

d/dx(2(49896/r) + 2πr²) = -99896/r² + 4πr

Setting this derivative equal to zero, we get:

-99896/r² + 4πr = 0

r³ = 99896/4π

r = 14.04 cm (approx.)

Substituting this value of r in the expression for total surface area, we get:

Total surface area = 2π(14.04)(49896/π(14.04)²) + 2π(14.04)²

Total surface area = 7524 cm²

Therefore, the total surface area of the cylindrical vessel is 7524 cm².
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A cylinderical vessel contains 49.896 litres of liquid. cost of painti...
Genius

GIVEN:

Volume of cylindrical vessel= 49.896 L

= 49.896× 1000 = 49896 cm³

[ 1 L = 1000 cm³]

Cost of painting at 2 paise per square cm= ₹ 95.04

Curved surface area of cylinder= cost / rate

Curved surface area of cylinder=95.04/.02

Curved surface area of cylinder= 4752 cm²

Let r and h be the radius and height of the cylinder .

Curved surface area of cylinder= 2πrh

2πrh = 4752……..(1)

Volume of Cylinder= πr²h

πr²h= 49896 ……….(2)

From equation 1 and 2

2πrh/πr²h = 4752/49896

2/r = 594/6237

r= 21 cm

Put this value of r in eq 1

2πrh = 4752

2 × (22/7)× 21× h= 4752

2×22×3×h = 4752

h= 4752/2×22×3

h= 36 cm

Total surface area of the cylindrical vessel= 2πr(h+r)

= 2×(22/7)×21(21+36)

= 2×22×3(57)

= 7524 cm²

Hence, the total surface area of the cylindrical vessel is 7524 cm²

Hope this will help you....
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A cylinderical vessel contains 49.896 litres of liquid. cost of painting its CSA at 2 paise/sq cm is Rs. 95.04.Then its total surface area is ______.a)5724 cm2b)7524cm2c)5742cm2d)None of theseCorrect answer is option 'B'. Can you explain this answer?
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