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Volume (mL) of H2C2O4. 2H2O solution to prepare 0.10 M from 1.575g of it is ?
Correct answer is '125'. Can you explain this answer?
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Volume (mL) of H2C2O4. 2H2O solution to prepare 0.10 M from 1.575g of ...
Calculation of Volume of H2C2O4.2H2O solution
To calculate the volume of the H2C2O4.2H2O solution needed to prepare a 0.10 M solution, we need to use the formula:
Molarity (M) = (moles of solute) / (volume of solution in liters)
Step 1: Convert the mass of H2C2O4.2H2O to moles
The molar mass of H2C2O4.2H2O can be calculated as follows:
H = 1.01 g/mol (2 atoms)
C = 12.01 g/mol (2 atoms)
O = 16.00 g/mol (6 atoms)
H2O = 18.02 g/mol (2 molecules)
Molar mass of H2C2O4.2H2O = (2 * 1.01) + (2 * 12.01) + (6 * 16.00) + (2 * 18.02) = 126.07 g/mol
Now, we can calculate the number of moles of H2C2O4.2H2O:
moles = mass / molar mass = 1.575 g / 126.07 g/mol = 0.0125 mol
Step 2: Calculate the volume of the solution
Using the formula mentioned above, we can rearrange it to solve for volume:
volume = (moles of solute) / (Molarity)
volume = 0.0125 mol / 0.10 M = 0.125 L
Since the volume is usually expressed in milliliters (mL), we can convert liters to milliliters:
0.125 L * 1000 mL/L = 125 mL
Therefore, the volume of the H2C2O4.2H2O solution needed to prepare a 0.10 M solution is 125 mL.
To calculate the volume of the H2C2O4.2H2O solution needed to prepare a 0.10 M solution, we need to use the formula:
Molarity (M) = (moles of solute) / (volume of solution in liters)
Step 1: Convert the mass of H2C2O4.2H2O to moles
The molar mass of H2C2O4.2H2O can be calculated as follows:
H = 1.01 g/mol (2 atoms)
C = 12.01 g/mol (2 atoms)
O = 16.00 g/mol (6 atoms)
H2O = 18.02 g/mol (2 molecules)
Molar mass of H2C2O4.2H2O = (2 * 1.01) + (2 * 12.01) + (6 * 16.00) + (2 * 18.02) = 126.07 g/mol
Now, we can calculate the number of moles of H2C2O4.2H2O:
moles = mass / molar mass = 1.575 g / 126.07 g/mol = 0.0125 mol
Step 2: Calculate the volume of the solution
Using the formula mentioned above, we can rearrange it to solve for volume:
volume = (moles of solute) / (Molarity)
volume = 0.0125 mol / 0.10 M = 0.125 L
Since the volume is usually expressed in milliliters (mL), we can convert liters to milliliters:
0.125 L * 1000 mL/L = 125 mL
Therefore, the volume of the H2C2O4.2H2O solution needed to prepare a 0.10 M solution is 125 mL.
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Volume (mL) of H2C2O4. 2H2O solution to prepare 0.10 M from 1.575g of it is ?Correct answer is '125'. Can you explain this answer?
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Volume (mL) of H2C2O4. 2H2O solution to prepare 0.10 M from 1.575g of it is ?Correct answer is '125'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Volume (mL) of H2C2O4. 2H2O solution to prepare 0.10 M from 1.575g of it is ?Correct answer is '125'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Volume (mL) of H2C2O4. 2H2O solution to prepare 0.10 M from 1.575g of it is ?Correct answer is '125'. Can you explain this answer?.
Volume (mL) of H2C2O4. 2H2O solution to prepare 0.10 M from 1.575g of it is ?Correct answer is '125'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Volume (mL) of H2C2O4. 2H2O solution to prepare 0.10 M from 1.575g of it is ?Correct answer is '125'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Volume (mL) of H2C2O4. 2H2O solution to prepare 0.10 M from 1.575g of it is ?Correct answer is '125'. Can you explain this answer?.
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