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[OH–] in a solution prepared by mixing equal volumes of 0.3 M methyl amine (CH3NH2, Kb = 3.7 × 10–4) and 0.60 M CH3NH3+Cl– is (in the multiple of 10–4 M):Correct answer is between '1.84,1.86'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared
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the Chemistry exam syllabus. Information about [OH–] in a solution prepared by mixing equal volumes of 0.3 M methyl amine (CH3NH2, Kb = 3.7 × 10–4) and 0.60 M CH3NH3+Cl– is (in the multiple of 10–4 M):Correct answer is between '1.84,1.86'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam.
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[OH–] in a solution prepared by mixing equal volumes of 0.3 M methyl amine (CH3NH2, Kb = 3.7 × 10–4) and 0.60 M CH3NH3+Cl– is (in the multiple of 10–4 M):Correct answer is between '1.84,1.86'. Can you explain this answer?, a detailed solution for [OH–] in a solution prepared by mixing equal volumes of 0.3 M methyl amine (CH3NH2, Kb = 3.7 × 10–4) and 0.60 M CH3NH3+Cl– is (in the multiple of 10–4 M):Correct answer is between '1.84,1.86'. Can you explain this answer? has been provided alongside types of [OH–] in a solution prepared by mixing equal volumes of 0.3 M methyl amine (CH3NH2, Kb = 3.7 × 10–4) and 0.60 M CH3NH3+Cl– is (in the multiple of 10–4 M):Correct answer is between '1.84,1.86'. Can you explain this answer? theory, EduRev gives you an
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