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Calcium lactate is a salt of weak organic acid and strong base, represented as Ca(Lac)2. A saturated solution of Ca(Lac)2 contains 0.13 mole of this salt in 0.50 L solution. The pOH of this solution is 5.60. Assuming a complete dissociation of the salt, calculate Ka of lactic acid. [In the multiple of 10–4, up to first decimal place]
Correct answer is between '8.2,8.4'. Can you explain this answer?
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Calcium lactate is a salt of weak organic acid and strong base, repres...
For hydrolysis of weak acid and strong base ,PH=1/2(pkw+pka+loga) here a is lactate ion conc =2*.26 ,ph =14-poh
14-5.6= 1/2(14-logka+log.52)
logka =-3.084 thus
ka=8.24 ,*10-4
14-5.6= 1/2(14-logka+log.52)
logka =-3.084 thus
ka=8.24 ,*10-4
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Calcium lactate is a salt of weak organic acid and strong base, repres...
To find the Ka of lactic acid, we first need to find the concentration of lactic acid in the solution.
Since calcium lactate (Ca(Lac)2) completely dissociates in solution, we can assume that 0.13 moles of calcium lactate dissociate to form 0.26 moles of lactic acid.
The volume of the solution is 0.50 L, so the concentration of lactic acid is 0.26 moles / 0.50 L = 0.52 M.
Now, we need to find the concentration of hydroxide ions (OH-) in the solution. The pOH is given as 5.60, so the concentration of hydroxide ions can be calculated using the equation:
pOH = -log[OH-]
5.60 = -log[OH-]
[OH-] = 10^(-5.60) = 2.51 x 10^(-6) M
Since the concentration of hydroxide ions is equal to the concentration of lactic acid (assuming a 1:1 stoichiometry), the concentration of lactic acid is also 2.51 x 10^(-6) M.
Now, we can use the equilibrium equation for lactic acid to find the Ka:
Ka = [H+][Lac-] / [HLac]
Since the concentration of lactic acid is equal to the concentration of hydroxide ions, we can substitute 2.51 x 10^(-6) M for both [H+] and [Lac-]:
Ka = (2.51 x 10^(-6) M)(2.51 x 10^(-6) M) / (0.52 M)
Ka = 6.3 x 10^(-12)
Therefore, the Ka of lactic acid is 6.3 x 10^(-12) (in the multiple of 10).
Since calcium lactate (Ca(Lac)2) completely dissociates in solution, we can assume that 0.13 moles of calcium lactate dissociate to form 0.26 moles of lactic acid.
The volume of the solution is 0.50 L, so the concentration of lactic acid is 0.26 moles / 0.50 L = 0.52 M.
Now, we need to find the concentration of hydroxide ions (OH-) in the solution. The pOH is given as 5.60, so the concentration of hydroxide ions can be calculated using the equation:
pOH = -log[OH-]
5.60 = -log[OH-]
[OH-] = 10^(-5.60) = 2.51 x 10^(-6) M
Since the concentration of hydroxide ions is equal to the concentration of lactic acid (assuming a 1:1 stoichiometry), the concentration of lactic acid is also 2.51 x 10^(-6) M.
Now, we can use the equilibrium equation for lactic acid to find the Ka:
Ka = [H+][Lac-] / [HLac]
Since the concentration of lactic acid is equal to the concentration of hydroxide ions, we can substitute 2.51 x 10^(-6) M for both [H+] and [Lac-]:
Ka = (2.51 x 10^(-6) M)(2.51 x 10^(-6) M) / (0.52 M)
Ka = 6.3 x 10^(-12)
Therefore, the Ka of lactic acid is 6.3 x 10^(-12) (in the multiple of 10).
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Calcium lactate is a salt of weak organic acid and strong base, represented as Ca(Lac)2. A saturated solution of Ca(Lac)2 contains 0.13 mole of this salt in 0.50 L solution. The pOH of this solution is 5.60. Assuming a complete dissociation of the salt, calculate Ka of lactic acid.[In the multiple of 10–4, up to first decimal place]Correct answer is between '8.2,8.4'. Can you explain this answer?
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Calcium lactate is a salt of weak organic acid and strong base, represented as Ca(Lac)2. A saturated solution of Ca(Lac)2 contains 0.13 mole of this salt in 0.50 L solution. The pOH of this solution is 5.60. Assuming a complete dissociation of the salt, calculate Ka of lactic acid.[In the multiple of 10–4, up to first decimal place]Correct answer is between '8.2,8.4'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Calcium lactate is a salt of weak organic acid and strong base, represented as Ca(Lac)2. A saturated solution of Ca(Lac)2 contains 0.13 mole of this salt in 0.50 L solution. The pOH of this solution is 5.60. Assuming a complete dissociation of the salt, calculate Ka of lactic acid.[In the multiple of 10–4, up to first decimal place]Correct answer is between '8.2,8.4'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calcium lactate is a salt of weak organic acid and strong base, represented as Ca(Lac)2. A saturated solution of Ca(Lac)2 contains 0.13 mole of this salt in 0.50 L solution. The pOH of this solution is 5.60. Assuming a complete dissociation of the salt, calculate Ka of lactic acid.[In the multiple of 10–4, up to first decimal place]Correct answer is between '8.2,8.4'. Can you explain this answer?.
Calcium lactate is a salt of weak organic acid and strong base, represented as Ca(Lac)2. A saturated solution of Ca(Lac)2 contains 0.13 mole of this salt in 0.50 L solution. The pOH of this solution is 5.60. Assuming a complete dissociation of the salt, calculate Ka of lactic acid.[In the multiple of 10–4, up to first decimal place]Correct answer is between '8.2,8.4'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Calcium lactate is a salt of weak organic acid and strong base, represented as Ca(Lac)2. A saturated solution of Ca(Lac)2 contains 0.13 mole of this salt in 0.50 L solution. The pOH of this solution is 5.60. Assuming a complete dissociation of the salt, calculate Ka of lactic acid.[In the multiple of 10–4, up to first decimal place]Correct answer is between '8.2,8.4'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calcium lactate is a salt of weak organic acid and strong base, represented as Ca(Lac)2. A saturated solution of Ca(Lac)2 contains 0.13 mole of this salt in 0.50 L solution. The pOH of this solution is 5.60. Assuming a complete dissociation of the salt, calculate Ka of lactic acid.[In the multiple of 10–4, up to first decimal place]Correct answer is between '8.2,8.4'. Can you explain this answer?.
Solutions for Calcium lactate is a salt of weak organic acid and strong base, represented as Ca(Lac)2. A saturated solution of Ca(Lac)2 contains 0.13 mole of this salt in 0.50 L solution. The pOH of this solution is 5.60. Assuming a complete dissociation of the salt, calculate Ka of lactic acid.[In the multiple of 10–4, up to first decimal place]Correct answer is between '8.2,8.4'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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Calcium lactate is a salt of weak organic acid and strong base, represented as Ca(Lac)2. A saturated solution of Ca(Lac)2 contains 0.13 mole of this salt in 0.50 L solution. The pOH of this solution is 5.60. Assuming a complete dissociation of the salt, calculate Ka of lactic acid.[In the multiple of 10–4, up to first decimal place]Correct answer is between '8.2,8.4'. Can you explain this answer?, a detailed solution for Calcium lactate is a salt of weak organic acid and strong base, represented as Ca(Lac)2. A saturated solution of Ca(Lac)2 contains 0.13 mole of this salt in 0.50 L solution. The pOH of this solution is 5.60. Assuming a complete dissociation of the salt, calculate Ka of lactic acid.[In the multiple of 10–4, up to first decimal place]Correct answer is between '8.2,8.4'. Can you explain this answer? has been provided alongside types of Calcium lactate is a salt of weak organic acid and strong base, represented as Ca(Lac)2. A saturated solution of Ca(Lac)2 contains 0.13 mole of this salt in 0.50 L solution. The pOH of this solution is 5.60. Assuming a complete dissociation of the salt, calculate Ka of lactic acid.[In the multiple of 10–4, up to first decimal place]Correct answer is between '8.2,8.4'. Can you explain this answer? theory, EduRev gives you an
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