Chemistry Exam > Chemistry Questions > Oxygen has a positive oxidation state in:a)O2...
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Oxygen has a positive oxidation state in:
- a)O2F2
- b)Na2O2
- c)Cl2O2
- d)H2O2
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Oxygen has a positive oxidation state in:a)O2F2b)Na2O2c)Cl2O2d)H2O2Cor...
**Oxygen Oxidation States**
Oxidation state is a measure of the degree of oxidation of an atom in a compound. It indicates the number of electrons an atom has gained or lost in order to form the compound. Oxygen can have different oxidation states depending on the compound it is in.
**Oxygen in O2F2**
In O2F2, oxygen has a positive oxidation state. This can be determined by assigning oxidation numbers to each element in the compound and applying the rules for assigning oxidation numbers.
The oxidation number of fluorine is always -1 in compounds, as it is the most electronegative element. Since there are two fluorine atoms in O2F2, the total oxidation number for fluorine is -2.
The compound is neutral, so the sum of the oxidation numbers must be zero. Therefore, the oxidation number of oxygen can be calculated as follows:
2x + (-2) = 0
2x = 2
x = 1
Therefore, oxygen has an oxidation state of +1 in O2F2.
**Explanation of the Answer**
The correct answer is option 'A' because in O2F2, oxygen has a positive oxidation state of +1. This is determined by applying the rules for assigning oxidation numbers and considering the overall charge of the compound.
It is important to note that the other options given (Na2O2, Cl2O2, and H2O2) do not have oxygen with a positive oxidation state.
In Na2O2, the oxidation number of sodium is +1 (as it is an alkali metal) and the oxidation number of oxygen is -1. The compound is neutral, so the sum of the oxidation numbers must be zero. Therefore, the oxidation state of oxygen is -1.
In Cl2O2, the oxidation number of chlorine is 0 (as it is a diatomic molecule) and the oxidation number of oxygen is -1. The compound is neutral, so the sum of the oxidation numbers must be zero. Therefore, the oxidation state of oxygen is -1.
In H2O2, the oxidation number of hydrogen is +1 (as it is an alkali metal) and the oxidation number of oxygen is -1. The compound is neutral, so the sum of the oxidation numbers must be zero. Therefore, the oxidation state of oxygen is -1.
Therefore, the only compound in which oxygen has a positive oxidation state is O2F2.
Oxidation state is a measure of the degree of oxidation of an atom in a compound. It indicates the number of electrons an atom has gained or lost in order to form the compound. Oxygen can have different oxidation states depending on the compound it is in.
**Oxygen in O2F2**
In O2F2, oxygen has a positive oxidation state. This can be determined by assigning oxidation numbers to each element in the compound and applying the rules for assigning oxidation numbers.
The oxidation number of fluorine is always -1 in compounds, as it is the most electronegative element. Since there are two fluorine atoms in O2F2, the total oxidation number for fluorine is -2.
The compound is neutral, so the sum of the oxidation numbers must be zero. Therefore, the oxidation number of oxygen can be calculated as follows:
2x + (-2) = 0
2x = 2
x = 1
Therefore, oxygen has an oxidation state of +1 in O2F2.
**Explanation of the Answer**
The correct answer is option 'A' because in O2F2, oxygen has a positive oxidation state of +1. This is determined by applying the rules for assigning oxidation numbers and considering the overall charge of the compound.
It is important to note that the other options given (Na2O2, Cl2O2, and H2O2) do not have oxygen with a positive oxidation state.
In Na2O2, the oxidation number of sodium is +1 (as it is an alkali metal) and the oxidation number of oxygen is -1. The compound is neutral, so the sum of the oxidation numbers must be zero. Therefore, the oxidation state of oxygen is -1.
In Cl2O2, the oxidation number of chlorine is 0 (as it is a diatomic molecule) and the oxidation number of oxygen is -1. The compound is neutral, so the sum of the oxidation numbers must be zero. Therefore, the oxidation state of oxygen is -1.
In H2O2, the oxidation number of hydrogen is +1 (as it is an alkali metal) and the oxidation number of oxygen is -1. The compound is neutral, so the sum of the oxidation numbers must be zero. Therefore, the oxidation state of oxygen is -1.
Therefore, the only compound in which oxygen has a positive oxidation state is O2F2.
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Community Answer
Oxygen has a positive oxidation state in:a)O2F2b)Na2O2c)Cl2O2d)H2O2Cor...
F is more electronegative than O.
So, in a, 2x -2 = 0, x = 1
So, in a, 2x -2 = 0, x = 1
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