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Arrange the following in decreasing order of stretching frequency  of C-O bond (cm–1):
(I) Mo(CO)3(NMe3)3              (II) Mo(CO)3[P(OPh)3]3
(III) Mo(CO)3(PMe3)3            (IV) Mo(CO)3(PCl3)3
  • a)
    IV > III > II > I
  • b)
    I > III > II > IV
  • c)
    I > II > III > IV
  • d)
    IV > II > III > I
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Arrange the following in decreasing order of stretching frequency of C...
Correct answer is  option (D).
Decreasing Order of Stretching Frequency of C-O Bond (cm–1):

- IV) Mo(CO)3(PCl3)3
- II) Mo(CO)3[P(OPh)3]3
- III) Mo(CO)3(PMe3)3
- I) Mo(CO)3(NMe3)3

The decreasing order of stretching frequency of the C-O bond (cm–1) can be explained by considering the electron-donating or withdrawing ability of the ligands attached to the metal center. The higher the electron-donating ability of the ligands, the more electron density will be present on the metal center, which will weaken the C-O bond and result in a lower stretching frequency.

In this case, the order can be explained as follows:
- Mo(CO)3(PCl3)3 (IV): The PCl3 ligands are strong electron-withdrawing groups, which causes the C-O bond to be stronger and have a higher stretching frequency.
- Mo(CO)3[P(OPh)3]3 (II): The P(OPh)3 ligands are less electron-withdrawing than PCl3, resulting in a weaker C-O bond and a lower stretching frequency compared to IV.
- Mo(CO)3(PMe3)3 (III): The PMe3 ligands are electron-donating groups, which further weakens the C-O bond and lowers the stretching frequency compared to II.
- Mo(CO)3(NMe3)3 (I): The NMe3 ligands are strong electron-donating groups, which results in the weakest C-O bond and the lowest stretching frequency among all the complexes.

Therefore, the correct order is IV > II > III > I.
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Arrange the following in decreasing order of stretching frequency of C...
Correct answer is  option (D).
Decreasing Order of Stretching Frequency of C-O Bond (cm–1):

- IV) Mo(CO)3(PCl3)3
- II) Mo(CO)3[P(OPh)3]3
- III) Mo(CO)3(PMe3)3
- I) Mo(CO)3(NMe3)3

The decreasing order of stretching frequency of the C-O bond (cm–1) can be explained by considering the electron-donating or withdrawing ability of the ligands attached to the metal center. The higher the electron-donating ability of the ligands, the more electron density will be present on the metal center, which will weaken the C-O bond and result in a lower stretching frequency.

In this case, the order can be explained as follows:
- Mo(CO)3(PCl3)3 (IV): The PCl3 ligands are strong electron-withdrawing groups, which causes the C-O bond to be stronger and have a higher stretching frequency.
- Mo(CO)3[P(OPh)3]3 (II): The P(OPh)3 ligands are less electron-withdrawing than PCl3, resulting in a weaker C-O bond and a lower stretching frequency compared to IV.
- Mo(CO)3(PMe3)3 (III): The PMe3 ligands are electron-donating groups, which further weakens the C-O bond and lowers the stretching frequency compared to II.
- Mo(CO)3(NMe3)3 (I): The NMe3 ligands are strong electron-donating groups, which results in the weakest C-O bond and the lowest stretching frequency among all the complexes.

Therefore, the correct order is IV > II > III > I.
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Community Answer
Arrange the following in decreasing order of stretching frequency of C...
Electron donation increase  = stretching frequency is also increases
[here ,  Ed =  nme3>pme3>poph3>pcl3]
but in question asked decreasing order frequency
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Arrange the following in decreasing order of stretching frequency of C-O bond (cm–1):(I) Mo(CO)3(NMe3)3 (II) Mo(CO)3[P(OPh)3]3(III) Mo(CO)3(PMe3)3 (IV) Mo(CO)3(PCl3)3a)IV > III > II > Ib)I > III > II > IVc)I > II > III > IVd)IV > II > III > ICorrect answer is option 'D'. Can you explain this answer?
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Arrange the following in decreasing order of stretching frequency of C-O bond (cm–1):(I) Mo(CO)3(NMe3)3 (II) Mo(CO)3[P(OPh)3]3(III) Mo(CO)3(PMe3)3 (IV) Mo(CO)3(PCl3)3a)IV > III > II > Ib)I > III > II > IVc)I > II > III > IVd)IV > II > III > ICorrect answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Arrange the following in decreasing order of stretching frequency of C-O bond (cm–1):(I) Mo(CO)3(NMe3)3 (II) Mo(CO)3[P(OPh)3]3(III) Mo(CO)3(PMe3)3 (IV) Mo(CO)3(PCl3)3a)IV > III > II > Ib)I > III > II > IVc)I > II > III > IVd)IV > II > III > ICorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Arrange the following in decreasing order of stretching frequency of C-O bond (cm–1):(I) Mo(CO)3(NMe3)3 (II) Mo(CO)3[P(OPh)3]3(III) Mo(CO)3(PMe3)3 (IV) Mo(CO)3(PCl3)3a)IV > III > II > Ib)I > III > II > IVc)I > II > III > IVd)IV > II > III > ICorrect answer is option 'D'. Can you explain this answer?.
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