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0.2 M NaOH is titrated with 0.2 M, 20 ml, HA (Monobasic acid) till the equivalence point reached degree of dissociation of HA is supposed to be legible. Calculate the pH of the resulting solution at the end point. [Given Ka = 1.8 × 10–5]    
  • a)
    4.42    
  • b)
    8.89    
  • c)
    11.2    
  • d)
    7.0
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
0.2 M NaOH is titrated with 0.2 M, 20 ml, HA (Monobasic acid) till the...
To calculate the pH of the resulting solution at the end point, we need to determine the concentration of the acid and the conjugate base at the equivalence point.

First, let's determine the initial moles of HA in the 20 ml of 0.2 M HA solution:
moles of HA = concentration of HA x volume of HA solution
moles of HA = 0.2 M x 0.020 L = 0.004 moles

Since the acid is monoprotic and dissociates according to the reaction:
HA ⇌ H+ + A-

The moles of H+ and A- at the equivalence point will be equal. Therefore, the concentration of H+ and A- at the equivalence point will be:
[H+] = [A-] = 0.004 moles / 0.020 L = 0.2 M

Since the solution is in water, the concentration of OH- ions will be equal to the concentration of H+ ions at the equivalence point, which is 0.2 M.

Now, let's calculate the pOH at the equivalence point:
pOH = -log10[OH-] = -log10(0.2) = 0.70

Since pH + pOH = 14, we can calculate the pH at the equivalence point:
pH = 14 - pOH = 14 - 0.70 = 13.3

Therefore, the pH of the resulting solution at the end point is approximately 13.3.
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0.2 M NaOH is titrated with 0.2 M, 20 ml, HA (Monobasic acid) till the equivalence point reached degree of dissociation of HA is supposed to be legible. Calculate the pH of the resulting solution at the end point. [Given Ka = 1.8 × 10–5] a)4.42 b)8.89 c)11.2 d)7.0Correct answer is option 'B'. Can you explain this answer?
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0.2 M NaOH is titrated with 0.2 M, 20 ml, HA (Monobasic acid) till the equivalence point reached degree of dissociation of HA is supposed to be legible. Calculate the pH of the resulting solution at the end point. [Given Ka = 1.8 × 10–5] a)4.42 b)8.89 c)11.2 d)7.0Correct answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about 0.2 M NaOH is titrated with 0.2 M, 20 ml, HA (Monobasic acid) till the equivalence point reached degree of dissociation of HA is supposed to be legible. Calculate the pH of the resulting solution at the end point. [Given Ka = 1.8 × 10–5] a)4.42 b)8.89 c)11.2 d)7.0Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.2 M NaOH is titrated with 0.2 M, 20 ml, HA (Monobasic acid) till the equivalence point reached degree of dissociation of HA is supposed to be legible. Calculate the pH of the resulting solution at the end point. [Given Ka = 1.8 × 10–5] a)4.42 b)8.89 c)11.2 d)7.0Correct answer is option 'B'. Can you explain this answer?.
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