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The insitu moisture content of a soil is 18% and its bulk unit weight is 19.65 
.The specific gravity of the soil solids is 2.7. The soil is to be excavated and transported to a construction site and then compacted to a minimum dry unit weight of 16.65 
at a moisture content of 20%. How many truck loads are needed to transport the excavated soil if each truck can carry 25 tons? Total volume of the compacted fill is 10,000
.The specific gravity of the soil solids is 2.7. The soil is to be excavated and transported to a construction site and then compacted to a minimum dry unit weight of 16.65 at a moisture content of 20%. How many truck loads are needed to transport the excavated soil if each truck can carry 25 tons? Total volume of the compacted fill is 10,000- a)638
- b)786
- c)1016
- d)1092
Correct answer is option 'B'. Can you explain this answer?
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The insitu moisture content of a soil is 18% and its bulk unit weight ...
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The insitu moisture content of a soil is 18% and its bulk unit weight ...
To solve this problem, we need to find the initial volume of the soil and the final volume of the compacted fill.
1. Find the initial volume of the soil:
The bulk unit weight of the soil is given as 19.65 kN/m3.
The moisture content of the soil is 18%, which means the soil contains 18% of water by weight.
Let's assume the weight of the soil solids is W, then the weight of water is 0.18W.
The total weight of the soil is the sum of the weight of the soil solids and the weight of water:
Total weight of the soil = W + 0.18W = 1.18W
The bulk unit weight of the soil is the total weight divided by the volume:
19.65 kN/m3 = (1.18W) / V
V = (1.18W) / 19.65
2. Find the final volume of the compacted fill:
The dry unit weight of the compacted fill is given as 16.65 kN/m3.
The moisture content of the compacted fill is 20%, which means the fill contains 20% of water by weight.
Let's assume the weight of the compacted fill solids is X, then the weight of water is 0.2X.
The total weight of the compacted fill is the sum of the weight of the fill solids and the weight of water:
Total weight of the compacted fill = X + 0.2X = 1.2X
The dry unit weight of the compacted fill is the total weight divided by the volume:
16.65 kN/m3 = (1.2X) / V
V = (1.2X) / 16.65
3. Find the volume of soil to be transported:
The volume of soil to be transported is the difference between the initial volume and the final volume:
Volume of soil to be transported = V - V = (1.18W) / 19.65 - (1.2X) / 16.65
4. Find the weight of the soil to be transported:
The weight of the soil to be transported is the weight of the soil solids minus the weight of the fill solids:
Weight of soil to be transported = W - X
5. Find the number of truck loads needed:
Each truck can carry 25 tons, which is equal to 25,000 kg.
The weight of soil to be transported divided by the weight each truck can carry gives the number of truck loads needed:
Number of truck loads = (Weight of soil to be transported) / (25,000 kg)
Note: The specific gravity of the soil solids is not needed to solve this problem.
Please provide the weight of the soil solids (W) and the weight of the fill solids (X) to continue the calculations.
1. Find the initial volume of the soil:
The bulk unit weight of the soil is given as 19.65 kN/m3.
The moisture content of the soil is 18%, which means the soil contains 18% of water by weight.
Let's assume the weight of the soil solids is W, then the weight of water is 0.18W.
The total weight of the soil is the sum of the weight of the soil solids and the weight of water:
Total weight of the soil = W + 0.18W = 1.18W
The bulk unit weight of the soil is the total weight divided by the volume:
19.65 kN/m3 = (1.18W) / V
V = (1.18W) / 19.65
2. Find the final volume of the compacted fill:
The dry unit weight of the compacted fill is given as 16.65 kN/m3.
The moisture content of the compacted fill is 20%, which means the fill contains 20% of water by weight.
Let's assume the weight of the compacted fill solids is X, then the weight of water is 0.2X.
The total weight of the compacted fill is the sum of the weight of the fill solids and the weight of water:
Total weight of the compacted fill = X + 0.2X = 1.2X
The dry unit weight of the compacted fill is the total weight divided by the volume:
16.65 kN/m3 = (1.2X) / V
V = (1.2X) / 16.65
3. Find the volume of soil to be transported:
The volume of soil to be transported is the difference between the initial volume and the final volume:
Volume of soil to be transported = V - V = (1.18W) / 19.65 - (1.2X) / 16.65
4. Find the weight of the soil to be transported:
The weight of the soil to be transported is the weight of the soil solids minus the weight of the fill solids:
Weight of soil to be transported = W - X
5. Find the number of truck loads needed:
Each truck can carry 25 tons, which is equal to 25,000 kg.
The weight of soil to be transported divided by the weight each truck can carry gives the number of truck loads needed:
Number of truck loads = (Weight of soil to be transported) / (25,000 kg)
Note: The specific gravity of the soil solids is not needed to solve this problem.
Please provide the weight of the soil solids (W) and the weight of the fill solids (X) to continue the calculations.
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The insitu moisture content of a soil is 18% and its bulk unit weight is 19.65 .The specific gravity of the soil solids is 2.7. The soil is to be excavated and transported to a construction site and then compacted to a minimum dry unit weight of 16.65 at a moisture content of 20%. How many truck loads are needed to transport the excavated soil if each truck can carry 25 tons? Total volume of the compacted fill is 10,000a)638b)786c) 1016d)1092Correct answer is option 'B'. Can you explain this answer?
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The insitu moisture content of a soil is 18% and its bulk unit weight is 19.65 .The specific gravity of the soil solids is 2.7. The soil is to be excavated and transported to a construction site and then compacted to a minimum dry unit weight of 16.65 at a moisture content of 20%. How many truck loads are needed to transport the excavated soil if each truck can carry 25 tons? Total volume of the compacted fill is 10,000a)638b)786c) 1016d)1092Correct answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The insitu moisture content of a soil is 18% and its bulk unit weight is 19.65 .The specific gravity of the soil solids is 2.7. The soil is to be excavated and transported to a construction site and then compacted to a minimum dry unit weight of 16.65 at a moisture content of 20%. How many truck loads are needed to transport the excavated soil if each truck can carry 25 tons? Total volume of the compacted fill is 10,000a)638b)786c) 1016d)1092Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The insitu moisture content of a soil is 18% and its bulk unit weight is 19.65 .The specific gravity of the soil solids is 2.7. The soil is to be excavated and transported to a construction site and then compacted to a minimum dry unit weight of 16.65 at a moisture content of 20%. How many truck loads are needed to transport the excavated soil if each truck can carry 25 tons? Total volume of the compacted fill is 10,000a)638b)786c) 1016d)1092Correct answer is option 'B'. Can you explain this answer?.
The insitu moisture content of a soil is 18% and its bulk unit weight is 19.65 .The specific gravity of the soil solids is 2.7. The soil is to be excavated and transported to a construction site and then compacted to a minimum dry unit weight of 16.65 at a moisture content of 20%. How many truck loads are needed to transport the excavated soil if each truck can carry 25 tons? Total volume of the compacted fill is 10,000a)638b)786c) 1016d)1092Correct answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The insitu moisture content of a soil is 18% and its bulk unit weight is 19.65 .The specific gravity of the soil solids is 2.7. The soil is to be excavated and transported to a construction site and then compacted to a minimum dry unit weight of 16.65 at a moisture content of 20%. How many truck loads are needed to transport the excavated soil if each truck can carry 25 tons? Total volume of the compacted fill is 10,000a)638b)786c) 1016d)1092Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The insitu moisture content of a soil is 18% and its bulk unit weight is 19.65 .The specific gravity of the soil solids is 2.7. The soil is to be excavated and transported to a construction site and then compacted to a minimum dry unit weight of 16.65 at a moisture content of 20%. How many truck loads are needed to transport the excavated soil if each truck can carry 25 tons? Total volume of the compacted fill is 10,000a)638b)786c) 1016d)1092Correct answer is option 'B'. Can you explain this answer?.
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