Mechanical Engineering Exam > Mechanical Engineering Questions > A steel shaft of 40 mm diameter is subjected ...
Start Learning for Free
A steel shaft of 40 mm diameter is subjected to a twisting moment of 1200 N.m. What will be the maximum shear stress (in N/mm2)?
Correct answer is between '95.2,96'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A steel shaft of 40 mm diameter is subjected to a twisting moment of 1...
Most Upvoted Answer
A steel shaft of 40 mm diameter is subjected to a twisting moment of 1...
Given data:
Diameter of the steel shaft (d) = 40 mm
Twisting moment (T) = 1200 N.m
Formula:
The maximum shear stress (τmax) in a solid circular shaft can be calculated using the formula:
τmax = (16T) / (πd^3)
Calculation:
Given that the diameter of the steel shaft is 40 mm, we can convert it to meters by dividing it by 1000:
d = 40 mm = 40/1000 m = 0.04 m
Substituting the values of T and d into the formula, we can calculate the maximum shear stress:
τmax = (16 × 1200) / (π × 0.04^3)
Simplifying the equation further:
τmax = (16 × 1200) / (3.14 × 0.000064)
τmax = 19200 / 0.00020096
τmax ≈ 95477.5 N/m^2
The maximum shear stress is approximately equal to 95477.5 N/m^2, which can be rounded to 95.5 N/mm^2.
Therefore, the correct answer lies between 95.2 N/mm^2 and 96 N/mm^2.
Diameter of the steel shaft (d) = 40 mm
Twisting moment (T) = 1200 N.m
Formula:
The maximum shear stress (τmax) in a solid circular shaft can be calculated using the formula:
τmax = (16T) / (πd^3)
Calculation:
Given that the diameter of the steel shaft is 40 mm, we can convert it to meters by dividing it by 1000:
d = 40 mm = 40/1000 m = 0.04 m
Substituting the values of T and d into the formula, we can calculate the maximum shear stress:
τmax = (16 × 1200) / (π × 0.04^3)
Simplifying the equation further:
τmax = (16 × 1200) / (3.14 × 0.000064)
τmax = 19200 / 0.00020096
τmax ≈ 95477.5 N/m^2
The maximum shear stress is approximately equal to 95477.5 N/m^2, which can be rounded to 95.5 N/mm^2.
Therefore, the correct answer lies between 95.2 N/mm^2 and 96 N/mm^2.
Attention Mechanical Engineering Students!
To make sure you are not studying endlessly, EduRev has designed Mechanical Engineering study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Mechanical Engineering.
|
Explore Courses for Mechanical Engineering exam
|
|
Similar Mechanical Engineering Doubts
Top Courses for Mechanical EngineeringView all
A steel shaft of 40 mm diameter is subjected to a twisting moment of 1200 N.m. What will be the maximum shear stress (in N/mm2)?Correct answer is between '95.2,96'. Can you explain this answer?
Question Description
A steel shaft of 40 mm diameter is subjected to a twisting moment of 1200 N.m. What will be the maximum shear stress (in N/mm2)?Correct answer is between '95.2,96'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A steel shaft of 40 mm diameter is subjected to a twisting moment of 1200 N.m. What will be the maximum shear stress (in N/mm2)?Correct answer is between '95.2,96'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A steel shaft of 40 mm diameter is subjected to a twisting moment of 1200 N.m. What will be the maximum shear stress (in N/mm2)?Correct answer is between '95.2,96'. Can you explain this answer?.
A steel shaft of 40 mm diameter is subjected to a twisting moment of 1200 N.m. What will be the maximum shear stress (in N/mm2)?Correct answer is between '95.2,96'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A steel shaft of 40 mm diameter is subjected to a twisting moment of 1200 N.m. What will be the maximum shear stress (in N/mm2)?Correct answer is between '95.2,96'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A steel shaft of 40 mm diameter is subjected to a twisting moment of 1200 N.m. What will be the maximum shear stress (in N/mm2)?Correct answer is between '95.2,96'. Can you explain this answer?.
Solutions for A steel shaft of 40 mm diameter is subjected to a twisting moment of 1200 N.m. What will be the maximum shear stress (in N/mm2)?Correct answer is between '95.2,96'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
Here you can find the meaning of A steel shaft of 40 mm diameter is subjected to a twisting moment of 1200 N.m. What will be the maximum shear stress (in N/mm2)?Correct answer is between '95.2,96'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A steel shaft of 40 mm diameter is subjected to a twisting moment of 1200 N.m. What will be the maximum shear stress (in N/mm2)?Correct answer is between '95.2,96'. Can you explain this answer?, a detailed solution for A steel shaft of 40 mm diameter is subjected to a twisting moment of 1200 N.m. What will be the maximum shear stress (in N/mm2)?Correct answer is between '95.2,96'. Can you explain this answer? has been provided alongside types of A steel shaft of 40 mm diameter is subjected to a twisting moment of 1200 N.m. What will be the maximum shear stress (in N/mm2)?Correct answer is between '95.2,96'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A steel shaft of 40 mm diameter is subjected to a twisting moment of 1200 N.m. What will be the maximum shear stress (in N/mm2)?Correct answer is between '95.2,96'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
|
|
Explore Courses for Mechanical Engineering exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup