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Consider ideal mixing of 2 moles of toluene and 2 moles of benzene at 1 atm and 300K. Calculate the sum of the values of ΔmixV, ΔmixU, ΔmixH, ΔmixG and ΔmixS for the process. (ln2=0.69, rounded up to first decimal place):
Correct answer is between '22.0,24.0'. Can you explain this answer?
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Consider ideal mixing of 2 moles of toluene and 2 moles of benzene at ...
Enthalpy and entropy change for the mixing process.
To calculate the enthalpy change for mixing, we need to know the enthalpy of mixing (ΔH_mix), which can be estimated using the regular solution model:
ΔH_mix = x_toluene x_benzene (A_benzene,toluene + A_toluene,benzene)
where x_toluene and x_benzene are the mole fractions of toluene and benzene, respectively, and A_benzene,toluene and A_toluene,benzene are the interaction parameters between the two components. For simplicity, we will assume that both interaction parameters are equal and have a value of -100 J/mol.
x_toluene = 2/(2+2) = 0.5
x_benzene = 2/(2+2) = 0.5
ΔH_mix = 0.5 x 0.5 (-100 + (-100)) = -50 J/mol
The negative sign indicates that the mixing process is exothermic.
To calculate the entropy change for mixing, we need to know the entropy of mixing (ΔS_mix), which can be estimated using the ideal mixing model:
ΔS_mix = -R (x_toluene ln x_toluene + x_benzene ln x_benzene)
where R is the gas constant. Plugging in the numbers, we get:
ΔS_mix = -8.31 J/mol K (0.5 ln 0.5 + 0.5 ln 0.5) = -8.31 J/mol K
The negative sign indicates that the mixing process is accompanied by a decrease in entropy.
Therefore, the sum of the values of enthalpy and entropy change for the mixing process is:
ΔH_mix + ΔS_mix = -50 J/mol + (-8.31 J/mol K) = -58.31 J/mol K
To calculate the enthalpy change for mixing, we need to know the enthalpy of mixing (ΔH_mix), which can be estimated using the regular solution model:
ΔH_mix = x_toluene x_benzene (A_benzene,toluene + A_toluene,benzene)
where x_toluene and x_benzene are the mole fractions of toluene and benzene, respectively, and A_benzene,toluene and A_toluene,benzene are the interaction parameters between the two components. For simplicity, we will assume that both interaction parameters are equal and have a value of -100 J/mol.
x_toluene = 2/(2+2) = 0.5
x_benzene = 2/(2+2) = 0.5
ΔH_mix = 0.5 x 0.5 (-100 + (-100)) = -50 J/mol
The negative sign indicates that the mixing process is exothermic.
To calculate the entropy change for mixing, we need to know the entropy of mixing (ΔS_mix), which can be estimated using the ideal mixing model:
ΔS_mix = -R (x_toluene ln x_toluene + x_benzene ln x_benzene)
where R is the gas constant. Plugging in the numbers, we get:
ΔS_mix = -8.31 J/mol K (0.5 ln 0.5 + 0.5 ln 0.5) = -8.31 J/mol K
The negative sign indicates that the mixing process is accompanied by a decrease in entropy.
Therefore, the sum of the values of enthalpy and entropy change for the mixing process is:
ΔH_mix + ΔS_mix = -50 J/mol + (-8.31 J/mol K) = -58.31 J/mol K
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Consider ideal mixing of 2 moles of toluene and 2 moles of benzene at 1 atm and 300K. Calculate the sum of the values of ΔmixV, ΔmixU, ΔmixH, ΔmixG and ΔmixS for the process. (ln2=0.69, rounded up to first decimal place):Correct answer is between '22.0,24.0'. Can you explain this answer?
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Consider ideal mixing of 2 moles of toluene and 2 moles of benzene at 1 atm and 300K. Calculate the sum of the values of ΔmixV, ΔmixU, ΔmixH, ΔmixG and ΔmixS for the process. (ln2=0.69, rounded up to first decimal place):Correct answer is between '22.0,24.0'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Consider ideal mixing of 2 moles of toluene and 2 moles of benzene at 1 atm and 300K. Calculate the sum of the values of ΔmixV, ΔmixU, ΔmixH, ΔmixG and ΔmixS for the process. (ln2=0.69, rounded up to first decimal place):Correct answer is between '22.0,24.0'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider ideal mixing of 2 moles of toluene and 2 moles of benzene at 1 atm and 300K. Calculate the sum of the values of ΔmixV, ΔmixU, ΔmixH, ΔmixG and ΔmixS for the process. (ln2=0.69, rounded up to first decimal place):Correct answer is between '22.0,24.0'. Can you explain this answer?.
Consider ideal mixing of 2 moles of toluene and 2 moles of benzene at 1 atm and 300K. Calculate the sum of the values of ΔmixV, ΔmixU, ΔmixH, ΔmixG and ΔmixS for the process. (ln2=0.69, rounded up to first decimal place):Correct answer is between '22.0,24.0'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Consider ideal mixing of 2 moles of toluene and 2 moles of benzene at 1 atm and 300K. Calculate the sum of the values of ΔmixV, ΔmixU, ΔmixH, ΔmixG and ΔmixS for the process. (ln2=0.69, rounded up to first decimal place):Correct answer is between '22.0,24.0'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider ideal mixing of 2 moles of toluene and 2 moles of benzene at 1 atm and 300K. Calculate the sum of the values of ΔmixV, ΔmixU, ΔmixH, ΔmixG and ΔmixS for the process. (ln2=0.69, rounded up to first decimal place):Correct answer is between '22.0,24.0'. Can you explain this answer?.
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Consider ideal mixing of 2 moles of toluene and 2 moles of benzene at 1 atm and 300K. Calculate the sum of the values of ΔmixV, ΔmixU, ΔmixH, ΔmixG and ΔmixS for the process. (ln2=0.69, rounded up to first decimal place):Correct answer is between '22.0,24.0'. Can you explain this answer?, a detailed solution for Consider ideal mixing of 2 moles of toluene and 2 moles of benzene at 1 atm and 300K. Calculate the sum of the values of ΔmixV, ΔmixU, ΔmixH, ΔmixG and ΔmixS for the process. (ln2=0.69, rounded up to first decimal place):Correct answer is between '22.0,24.0'. Can you explain this answer? has been provided alongside types of Consider ideal mixing of 2 moles of toluene and 2 moles of benzene at 1 atm and 300K. Calculate the sum of the values of ΔmixV, ΔmixU, ΔmixH, ΔmixG and ΔmixS for the process. (ln2=0.69, rounded up to first decimal place):Correct answer is between '22.0,24.0'. Can you explain this answer? theory, EduRev gives you an
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