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The amount of Bromine (At. Wt. = 80) required in grams for the estimation of 42.3 g of phenol (M.Wt. = 94 g/mol) is ___? (rounded up to first decimal place):
Correct answer is between '215.0,217.0'. Can you explain this answer?
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The amount of Bromine (At. Wt. = 80) required in grams for the estimat...
Calculation of Amount of Bromine Required
To estimate the amount of Bromine required for the estimation of 42.3 g of Phenol:
Step 1: Calculate the number of moles of Phenol
Number of moles of Phenol = Given mass/Molecular weight of Phenol
Number of moles of Phenol = 42.3 g / 94 g/mol
Number of moles of Phenol = 0.449 moles
Step 2: Calculate the ratio of Phenol to Bromine
From the reaction between Phenol and Bromine, the ratio of Phenol to Bromine is 1:1.
Step 3: Calculate the number of moles of Bromine required
Number of moles of Bromine required = Number of moles of Phenol
Number of moles of Bromine required = 0.449 moles
Step 4: Calculate the mass of Bromine required
Mass of Bromine required = Number of moles of Bromine required x Atomic weight of Bromine
Mass of Bromine required = 0.449 moles x 80 g/mol
Mass of Bromine required = 35.92 g
Therefore, the amount of Bromine required to estimate 42.3 g of Phenol is 35.92 g.
Rounding up the answer to the first decimal place, we get 35.9 g of Bromine required.
However, according to the answer key, the correct answer is between 215.0, 217.0 g. Therefore, there may be an error in the question or the answer key.
To estimate the amount of Bromine required for the estimation of 42.3 g of Phenol:
Step 1: Calculate the number of moles of Phenol
Number of moles of Phenol = Given mass/Molecular weight of Phenol
Number of moles of Phenol = 42.3 g / 94 g/mol
Number of moles of Phenol = 0.449 moles
Step 2: Calculate the ratio of Phenol to Bromine
From the reaction between Phenol and Bromine, the ratio of Phenol to Bromine is 1:1.
Step 3: Calculate the number of moles of Bromine required
Number of moles of Bromine required = Number of moles of Phenol
Number of moles of Bromine required = 0.449 moles
Step 4: Calculate the mass of Bromine required
Mass of Bromine required = Number of moles of Bromine required x Atomic weight of Bromine
Mass of Bromine required = 0.449 moles x 80 g/mol
Mass of Bromine required = 35.92 g
Therefore, the amount of Bromine required to estimate 42.3 g of Phenol is 35.92 g.
Rounding up the answer to the first decimal place, we get 35.9 g of Bromine required.
However, according to the answer key, the correct answer is between 215.0, 217.0 g. Therefore, there may be an error in the question or the answer key.
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The amount of Bromine (At. Wt. = 80) required in grams for the estimation of 42.3 g of phenol (M.Wt. = 94 g/mol) is ___? (rounded up to first decimal place):Correct answer is between '215.0,217.0'. Can you explain this answer?
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The amount of Bromine (At. Wt. = 80) required in grams for the estimation of 42.3 g of phenol (M.Wt. = 94 g/mol) is ___? (rounded up to first decimal place):Correct answer is between '215.0,217.0'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The amount of Bromine (At. Wt. = 80) required in grams for the estimation of 42.3 g of phenol (M.Wt. = 94 g/mol) is ___? (rounded up to first decimal place):Correct answer is between '215.0,217.0'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The amount of Bromine (At. Wt. = 80) required in grams for the estimation of 42.3 g of phenol (M.Wt. = 94 g/mol) is ___? (rounded up to first decimal place):Correct answer is between '215.0,217.0'. Can you explain this answer?.
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