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In the given figure POQ is a diameter of a circle with centre O and PQRS is a cyclic quadrilateral. SQ is joined. If ∠R = 138°, find ∠PQS.
  • a)
    90°
  • b)
    42°
  • c)
    48°
  • d)
    38°
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In the given figure POQ is a diameter of a circle with centre O and PQ...
We know that sum of opp angle of quad is 180
angle QRS+angle QPS=180
QPS=42
angle PSQ=90(angle in the semicircle is a right angle)
in triangle PQS 90+42+PQS=180
PQS=180_138=48
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Community Answer
In the given figure POQ is a diameter of a circle with centre O and PQ...
Since ABCD is a cyclic quadrilateral .
angle SRQ + angle SPQ = 180• ( sum of opposite sides of a quadrilateral is 180•)
138•+ angle SPQ=180•
angle SPQ=42•

since angle PSQ is the angle in a semi-circle .
angle PSQ =90•
Now , in ∆ QBC , we have
angle PQS +angle QSP +angle QPS = 180• (sum of angles of a triangle is 180•)
angle PQS +90• +42•=180•
angle PQS=48•
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In the given figure POQ is a diameter of a circle with centre O and PQRS is a cyclic quadrilateral. SQ is joined. If ∠R = 138°, find ∠PQS.a)90°b)42°c)48°d)38°Correct answer is option 'C'. Can you explain this answer?
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In the given figure POQ is a diameter of a circle with centre O and PQRS is a cyclic quadrilateral. SQ is joined. If ∠R = 138°, find ∠PQS.a)90°b)42°c)48°d)38°Correct answer is option 'C'. Can you explain this answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about In the given figure POQ is a diameter of a circle with centre O and PQRS is a cyclic quadrilateral. SQ is joined. If ∠R = 138°, find ∠PQS.a)90°b)42°c)48°d)38°Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the given figure POQ is a diameter of a circle with centre O and PQRS is a cyclic quadrilateral. SQ is joined. If ∠R = 138°, find ∠PQS.a)90°b)42°c)48°d)38°Correct answer is option 'C'. Can you explain this answer?.
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