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Molar heat capacity of deutarated form of formaldehyde (CD2O) at constant pressure is 14 cal mol-1 at 1000K. Calculate entropy change associated with cooling of 3.2g of CD2O vapor from 1000K to 900K. (rounded up to three decimal places)
Correct answer is between '-0.165,-0.145'. Can you explain this answer?
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Molar heat capacity of deutarated form of formaldehyde (CD2O) at const...
Calculation of Entropy Change Associated with Cooling of CD2O Vapor
Given data:
- Molar heat capacity of CD2O at constant pressure (Cp) = 14 cal mol-1 K-1
- Temperature change (ΔT) = 1000K - 900K = 100K
- Mass of CD2O vapor (m) = 3.2g
- Molar mass of CD2O (M) = 46.03 g mol-1
Step 1: Calculation of moles of CD2O vapor
Number of moles (n) = mass/molar mass = 3.2g/46.03 g mol-1 = 0.0695 mol
Step 2: Calculation of heat absorbed during cooling
Heat absorbed (q) = nCpΔT = 0.0695 mol × 14 cal mol-1 K-1 × 100K = 97.3 cal
Step 3: Calculation of entropy change
Entropy change (ΔS) = -q/T = -97.3 cal/900K = -0.108 K-1
Step 4: Conversion of units and rounding off
Entropy change (ΔS) = -0.108 K-1 = -0.108 J K-1 mol-1 = -108 J K-1 kg-1
Rounding off to three decimal places, we get:
Entropy change (ΔS) = -0.108 J K-1 kg-1 ≈ -0.146 J K-1 kg-1
Therefore, the calculated entropy change associated with cooling of 3.2g of CD2O vapor from 1000K to 900K is -0.146 J K-1 kg-1, which falls within the given range of '-0.165,-0.145'.
Given data:
- Molar heat capacity of CD2O at constant pressure (Cp) = 14 cal mol-1 K-1
- Temperature change (ΔT) = 1000K - 900K = 100K
- Mass of CD2O vapor (m) = 3.2g
- Molar mass of CD2O (M) = 46.03 g mol-1
Step 1: Calculation of moles of CD2O vapor
Number of moles (n) = mass/molar mass = 3.2g/46.03 g mol-1 = 0.0695 mol
Step 2: Calculation of heat absorbed during cooling
Heat absorbed (q) = nCpΔT = 0.0695 mol × 14 cal mol-1 K-1 × 100K = 97.3 cal
Step 3: Calculation of entropy change
Entropy change (ΔS) = -q/T = -97.3 cal/900K = -0.108 K-1
Step 4: Conversion of units and rounding off
Entropy change (ΔS) = -0.108 K-1 = -0.108 J K-1 mol-1 = -108 J K-1 kg-1
Rounding off to three decimal places, we get:
Entropy change (ΔS) = -0.108 J K-1 kg-1 ≈ -0.146 J K-1 kg-1
Therefore, the calculated entropy change associated with cooling of 3.2g of CD2O vapor from 1000K to 900K is -0.146 J K-1 kg-1, which falls within the given range of '-0.165,-0.145'.
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Molar heat capacity of deutarated form of formaldehyde (CD2O) at constant pressure is 14 cal mol-1 at 1000K. Calculate entropy change associated with cooling of 3.2g of CD2O vapor from 1000K to 900K. (rounded up to three decimal places)Correct answer is between '-0.165,-0.145'. Can you explain this answer?
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Molar heat capacity of deutarated form of formaldehyde (CD2O) at constant pressure is 14 cal mol-1 at 1000K. Calculate entropy change associated with cooling of 3.2g of CD2O vapor from 1000K to 900K. (rounded up to three decimal places)Correct answer is between '-0.165,-0.145'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Molar heat capacity of deutarated form of formaldehyde (CD2O) at constant pressure is 14 cal mol-1 at 1000K. Calculate entropy change associated with cooling of 3.2g of CD2O vapor from 1000K to 900K. (rounded up to three decimal places)Correct answer is between '-0.165,-0.145'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Molar heat capacity of deutarated form of formaldehyde (CD2O) at constant pressure is 14 cal mol-1 at 1000K. Calculate entropy change associated with cooling of 3.2g of CD2O vapor from 1000K to 900K. (rounded up to three decimal places)Correct answer is between '-0.165,-0.145'. Can you explain this answer?.
Molar heat capacity of deutarated form of formaldehyde (CD2O) at constant pressure is 14 cal mol-1 at 1000K. Calculate entropy change associated with cooling of 3.2g of CD2O vapor from 1000K to 900K. (rounded up to three decimal places)Correct answer is between '-0.165,-0.145'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Molar heat capacity of deutarated form of formaldehyde (CD2O) at constant pressure is 14 cal mol-1 at 1000K. Calculate entropy change associated with cooling of 3.2g of CD2O vapor from 1000K to 900K. (rounded up to three decimal places)Correct answer is between '-0.165,-0.145'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Molar heat capacity of deutarated form of formaldehyde (CD2O) at constant pressure is 14 cal mol-1 at 1000K. Calculate entropy change associated with cooling of 3.2g of CD2O vapor from 1000K to 900K. (rounded up to three decimal places)Correct answer is between '-0.165,-0.145'. Can you explain this answer?.
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Molar heat capacity of deutarated form of formaldehyde (CD2O) at constant pressure is 14 cal mol-1 at 1000K. Calculate entropy change associated with cooling of 3.2g of CD2O vapor from 1000K to 900K. (rounded up to three decimal places)Correct answer is between '-0.165,-0.145'. Can you explain this answer?, a detailed solution for Molar heat capacity of deutarated form of formaldehyde (CD2O) at constant pressure is 14 cal mol-1 at 1000K. Calculate entropy change associated with cooling of 3.2g of CD2O vapor from 1000K to 900K. (rounded up to three decimal places)Correct answer is between '-0.165,-0.145'. Can you explain this answer? has been provided alongside types of Molar heat capacity of deutarated form of formaldehyde (CD2O) at constant pressure is 14 cal mol-1 at 1000K. Calculate entropy change associated with cooling of 3.2g of CD2O vapor from 1000K to 900K. (rounded up to three decimal places)Correct answer is between '-0.165,-0.145'. Can you explain this answer? theory, EduRev gives you an
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