A complex cation is formed by Pt (in same oxidation state) with ligand...
Option c is correct.
in diammineethylenediaminedithiocyanato-S platinum (IV) ion
ammine is a monodentate ligand ,it is di- so 2 ammine are present.
ethylene diamine is a bidentate ligand , it is single so 2 eectrons are coordinated by it.
thiocyanato is a monodentate ligand and it is di- so it coordinates 2 electrons.
Therefore, adding them all 6 electrons are contributed and the coordination number of platinum becomes 6.
So., option c is correct as in other options the coordination number is not 6.
A complex cation is formed by Pt (in same oxidation state) with ligand...
Explanation:
Given Complex Cation:
- Pt ion with ligands forming a complex with a coordination number of six.
Correct IUPAC name:
- Diammineethylenediaminedithiocyanato-Splatinum(IV) ion
Reasoning:
- The complex has Pt in the +4 oxidation state, hence the Roman numeral IV in the name.
- The ligands are diammine, ethylenediamine, and dithiocyanato, forming a coordination number of six around Pt.
- The ligands are named in alphabetical order, so ethylenediamine comes before dithiocyanato in the name.
- The order of ligands in the name is based on their alphabetical order rather than their position around the central atom.
Incorrect Options:
a) Diammineethylenediaminedithiocyanato-Splatinum(II) ion - Incorrect oxidation state for Pt
b) Diamminedithiocyanato-Sethylenediamineplatinum(IV) ion - Incorrect ligand order
d) Diamminebis(ethylenediamine)dithiocyanate-S-platinum(IV) ion - Incorrect ligand order and naming
Therefore, the correct IUPAC name for the complex cation with Pt in the same oxidation state and a coordination number of six is Diammineethylenediaminedithiocyanato-Splatinum(IV) ion.