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The ‘brown ring’ formed at the junction of two layers in the test of nitrate is due to the formation of a complex ion, [Fe(H2O)5NO]2+. Which of the following statements are correct for this complex [u = 3.87 B.M.)
(i) Oxidation state of Fe is +1 and NO exists as NO+.
(ii) The complex ion is in octahedral geometry as attained by sp3d2 hybridisation.
(iii) The complex is paramagnetic and has three unpaired electrons due to transfer of  electron from NO to Fe2+.
(iv) The complex is in octahedral geometry as attained by d2sp3 hybridisation.
(v) The brown colour of the complex is attributed to d-d transition of electron.
  • a)
    (i), (ii) and (v)
  • b)
    (iii), (iv) and (v)
  • c)
    (i), (ii) and (iii)
  • d)
    (ii), (iii) and (v)
Correct answer is option 'C'. Can you explain this answer?
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Explanation:

(i) Oxidation state of Fe is 1 and NO exists as NO:

- The brown ring formed at the junction of two layers in the test for nitrate is due to the formation of a complex ion, [Fe(H2O)5NO]2+.
- In this complex, the oxidation state of Fe is +2. This can be determined by considering the overall charge of the complex and the known charges of the ligands (H2O and NO).
- The charges of the ligands, H2O and NO, are 0 and +1 respectively. Since there are 5 H2O ligands, the total charge contributed by the ligands is 0. Therefore, the overall charge of the complex must be +2, indicating that the oxidation state of Fe is +2.
- NO exists as NO in this complex, with a charge of +1.

(ii) The complex ion is in octahedral geometry as attained by sp3d2 hybridization:

- The complex ion [Fe(H2O)5NO]2+ has a coordination number of 6, which suggests an octahedral geometry.
- The octahedral geometry can be achieved through sp3d2 hybridization of the central Fe atom. In this hybridization, the 3d, 4s, and one of the 4p orbitals of Fe combine with two of the 4p orbitals of the two oxygens from the H2O ligands and one of the 2p orbitals of the nitrogen from the NO ligand.

(iii) The complex is paramagnetic and has three unpaired electrons due to the transfer of electrons from NO to Fe2+:

- Paramagnetic compounds have unpaired electrons and are attracted to a magnetic field.
- The complex ion [Fe(H2O)5NO]2+ has three unpaired electrons, which makes it paramagnetic. The unpaired electrons result from the transfer of one electron from the NO ligand to the Fe2+ ion.
- The transferred electron occupies one of the d orbitals of Fe, leading to the presence of unpaired electrons.

(iv) The complex is in octahedral geometry as attained by d2sp3 hybridization:

- This statement is incorrect. The correct hybridization for the complex ion [Fe(H2O)5NO]2+ is sp3d2.

(v) The brown color of the complex is attributed to d-d transition of electrons:

- The brown color of the complex is indeed attributed to d-d transitions of electrons.
- When electrons in the d orbitals of the transition metal ion absorb light, they can transition from one d orbital to another.
- These transitions involve the absorption of specific wavelengths of light, and the remaining wavelengths are transmitted, giving the complex its characteristic color.
- In the case of the brown ring test, the absorption of specific wavelengths of light by the complex results in the observed brown color.
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Read the passage given below and answer the following questions:The transition metals when exposed to oxygen at low and intermediate temperatures form thin, protective oxide films of up to some thousands of Angstroms in thickness. Transition metal oxides lie between the extremes of ionic and covalent binary compounds formed by elements from the left or right side of the periodic table. They range from metallic to semiconducting and deviate by both large and small degrees from stoichiometry. Since d-electron bonding levels are involved, the cations-exist in various valence states and hence give rise to a large number of oxides. The crystal structures are often classified by considering a cubic or hexagonal close-packed lattice of one set of ions with the other set of ions filling the octahedral or tetrahedral interstices. The actual oxide structures, however, generally show departures from such regular arrays due in part to distortions caused by packing of ions of different size and to ligand field effects. These distortions depend not only on the number of d-electrons but also on the valence and the position of the transition metal in a period or group.In the following questions, a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices on the basis of the above passage.Assertion (

The ‘brown ring’ formed at the junction of two layers in the test of nitrate is due to the formation of a complex ion, [Fe(H2O)5NO]2+. Which of the following statements are correct for this complex [u = 3.87 B.M.)(i) Oxidation state of Fe is +1 and NO exists as NO+.(ii) The complex ion is in octahedral geometry as attained by sp3d2 hybridisation.(iii) The complex is paramagnetic and has three unpaired electrons due to transfer of electron from NO to Fe2+.(iv) The complex is in octahedral geometry as attained by d2sp3 hybridisation.(v) The brown colour of the complex is attributed to d-d transition of electron.a)(i), (ii) and (v)b)(iii), (iv) and (v)c)(i), (ii) and (iii)d)(ii), (iii) and (v)Correct answer is option 'C'. Can you explain this answer?
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The ‘brown ring’ formed at the junction of two layers in the test of nitrate is due to the formation of a complex ion, [Fe(H2O)5NO]2+. Which of the following statements are correct for this complex [u = 3.87 B.M.)(i) Oxidation state of Fe is +1 and NO exists as NO+.(ii) The complex ion is in octahedral geometry as attained by sp3d2 hybridisation.(iii) The complex is paramagnetic and has three unpaired electrons due to transfer of electron from NO to Fe2+.(iv) The complex is in octahedral geometry as attained by d2sp3 hybridisation.(v) The brown colour of the complex is attributed to d-d transition of electron.a)(i), (ii) and (v)b)(iii), (iv) and (v)c)(i), (ii) and (iii)d)(ii), (iii) and (v)Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The ‘brown ring’ formed at the junction of two layers in the test of nitrate is due to the formation of a complex ion, [Fe(H2O)5NO]2+. Which of the following statements are correct for this complex [u = 3.87 B.M.)(i) Oxidation state of Fe is +1 and NO exists as NO+.(ii) The complex ion is in octahedral geometry as attained by sp3d2 hybridisation.(iii) The complex is paramagnetic and has three unpaired electrons due to transfer of electron from NO to Fe2+.(iv) The complex is in octahedral geometry as attained by d2sp3 hybridisation.(v) The brown colour of the complex is attributed to d-d transition of electron.a)(i), (ii) and (v)b)(iii), (iv) and (v)c)(i), (ii) and (iii)d)(ii), (iii) and (v)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The ‘brown ring’ formed at the junction of two layers in the test of nitrate is due to the formation of a complex ion, [Fe(H2O)5NO]2+. Which of the following statements are correct for this complex [u = 3.87 B.M.)(i) Oxidation state of Fe is +1 and NO exists as NO+.(ii) The complex ion is in octahedral geometry as attained by sp3d2 hybridisation.(iii) The complex is paramagnetic and has three unpaired electrons due to transfer of electron from NO to Fe2+.(iv) The complex is in octahedral geometry as attained by d2sp3 hybridisation.(v) The brown colour of the complex is attributed to d-d transition of electron.a)(i), (ii) and (v)b)(iii), (iv) and (v)c)(i), (ii) and (iii)d)(ii), (iii) and (v)Correct answer is option 'C'. Can you explain this answer?.
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