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The alkyl halide C4H9Br(A) reacts with alcoholic KOH and gives an alkene (B), which reacts withbromide to give dibromide (C). (C) is transformed with KOH & sodamide to gas (D) which forms aprecipitate when passed through an ammonical silver nitrate solution. Total number of sp3 carbonpresent in C and D would be:Correct answer is '6'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The alkyl halide C4H9Br(A) reacts with alcoholic KOH and gives an alkene (B), which reacts withbromide to give dibromide (C). (C) is transformed with KOH & sodamide to gas (D) which forms aprecipitate when passed through an ammonical silver nitrate solution. Total number of sp3 carbonpresent in C and D would be:Correct answer is '6'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The alkyl halide C4H9Br(A) reacts with alcoholic KOH and gives an alkene (B), which reacts withbromide to give dibromide (C). (C) is transformed with KOH & sodamide to gas (D) which forms aprecipitate when passed through an ammonical silver nitrate solution. Total number of sp3 carbonpresent in C and D would be:Correct answer is '6'. Can you explain this answer?.

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Here you can find the meaning of The alkyl halide C4H9Br(A) reacts with alcoholic KOH and gives an alkene (B), which reacts withbromide to give dibromide (C). (C) is transformed with KOH & sodamide to gas (D) which forms aprecipitate when passed through an ammonical silver nitrate solution. Total number of sp3 carbonpresent in C and D would be:Correct answer is '6'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The alkyl halide C4H9Br(A) reacts with alcoholic KOH and gives an alkene (B), which reacts withbromide to give dibromide (C). (C) is transformed with KOH & sodamide to gas (D) which forms aprecipitate when passed through an ammonical silver nitrate solution. Total number of sp3 carbonpresent in C and D would be:Correct answer is '6'. Can you explain this answer?, a detailed solution for The alkyl halide C4H9Br(A) reacts with alcoholic KOH and gives an alkene (B), which reacts withbromide to give dibromide (C). (C) is transformed with KOH & sodamide to gas (D) which forms aprecipitate when passed through an ammonical silver nitrate solution. Total number of sp3 carbonpresent in C and D would be:Correct answer is '6'. Can you explain this answer? has been provided alongside types of The alkyl halide C4H9Br(A) reacts with alcoholic KOH and gives an alkene (B), which reacts withbromide to give dibromide (C). (C) is transformed with KOH & sodamide to gas (D) which forms aprecipitate when passed through an ammonical silver nitrate solution. Total number of sp3 carbonpresent in C and D would be:Correct answer is '6'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The alkyl halide C4H9Br(A) reacts with alcoholic KOH and gives an alkene (B), which reacts withbromide to give dibromide (C). (C) is transformed with KOH & sodamide to gas (D) which forms aprecipitate when passed through an ammonical silver nitrate solution. Total number of sp3 carbonpresent in C and D would be:Correct answer is '6'. Can you explain this answer? tests, examples and also practice Chemistry tests.