Class 12 Exam > Class 12 Questions > Arrange the following in order of increasing ...
Start Learning for Free
Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyaniline
- a)p – methoxyaniline p – nitroaniline < aniline < p – toluidine
- b)p – nitroaniline < aniline < p – toluidine < p – methoxyaniline
- c)aniline < p – methoxyaniline p – nitroaniline < p – toluidine
- d)p – nitroaniline < aniline< p – methoxyaniline < p – toluidine
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
Arrange the following in order of increasing basicity: aniline, p R...
-OMe group at p position will increase the basicity more tha normal –CH3 group at p position. While presence of –NO2 at position will decrease the basicity.
Most Upvoted Answer
Arrange the following in order of increasing basicity: aniline, p R...
Explanation:
Basicity is the ability of a compound to donate a pair of electrons. The more stable the conjugate acid, the weaker the base. The stability of the conjugate acid depends on the electron-donating/withdrawing groups present on the ring. The order of basicity of the given compounds is:
1. p-methoxyaniline
2. p-nitroaniline
3. aniline
4. p-toluidine
Reasoning:
p-methoxyaniline:
In p-methoxyaniline, the methoxy group (-OCH3) is an electron-donating group that increases the electron density on the nitrogen atom. This makes the lone pair of electrons on the nitrogen atom more available for protonation. Therefore, p-methoxyaniline is the most basic compound among the given compounds.
p-nitroaniline:
In p-nitroaniline, the nitro group (-NO2) is an electron-withdrawing group that decreases the electron density on the nitrogen atom. This makes the lone pair of electrons on the nitrogen atom less available for protonation. Therefore, p-nitroaniline is less basic than p-methoxyaniline.
aniline:
In aniline, there are no electron-donating or electron-withdrawing groups present on the ring. Therefore, aniline is less basic than p-methoxyaniline and p-nitroaniline.
p-toluidine:
In p-toluidine, the methyl group (-CH3) is an electron-donating group that increases the electron density on the nitrogen atom. However, it is not as effective as the methoxy group in p-methoxyaniline. Therefore, p-toluidine is less basic than p-methoxyaniline.
Therefore, the correct order of increasing basicity is: p-nitroaniline < aniline="" />< p-toluidine="" />< />
Option B: p-nitroaniline aniline p-toluidine p-methoxyaniline is the correct order of increasing basicity.
Basicity is the ability of a compound to donate a pair of electrons. The more stable the conjugate acid, the weaker the base. The stability of the conjugate acid depends on the electron-donating/withdrawing groups present on the ring. The order of basicity of the given compounds is:
1. p-methoxyaniline
2. p-nitroaniline
3. aniline
4. p-toluidine
Reasoning:
p-methoxyaniline:
In p-methoxyaniline, the methoxy group (-OCH3) is an electron-donating group that increases the electron density on the nitrogen atom. This makes the lone pair of electrons on the nitrogen atom more available for protonation. Therefore, p-methoxyaniline is the most basic compound among the given compounds.
p-nitroaniline:
In p-nitroaniline, the nitro group (-NO2) is an electron-withdrawing group that decreases the electron density on the nitrogen atom. This makes the lone pair of electrons on the nitrogen atom less available for protonation. Therefore, p-nitroaniline is less basic than p-methoxyaniline.
aniline:
In aniline, there are no electron-donating or electron-withdrawing groups present on the ring. Therefore, aniline is less basic than p-methoxyaniline and p-nitroaniline.
p-toluidine:
In p-toluidine, the methyl group (-CH3) is an electron-donating group that increases the electron density on the nitrogen atom. However, it is not as effective as the methoxy group in p-methoxyaniline. Therefore, p-toluidine is less basic than p-methoxyaniline.
Therefore, the correct order of increasing basicity is: p-nitroaniline < aniline="" />< p-toluidine="" />< />
Option B: p-nitroaniline aniline p-toluidine p-methoxyaniline is the correct order of increasing basicity.
|
Explore Courses for Class 12 exam
|
|
Similar Class 12 Doubts
Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer?
Question Description
Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer?.
Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup