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Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyaniline
- a)p – methoxyaniline p – nitroaniline < aniline < p – toluidine
- b)p – nitroaniline < aniline < p – toluidine < p – methoxyaniline
- c)aniline < p – methoxyaniline p – nitroaniline < p – toluidine
- d)p – nitroaniline < aniline< p – methoxyaniline < p – toluidine
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Arrange the following in order of increasing basicity: aniline, p R...
-OMe group at p position will increase the basicity more tha normal –CH3 group at p position. While presence of –NO2 at position will decrease the basicity.
Most Upvoted Answer
Arrange the following in order of increasing basicity: aniline, p R...
Explanation:
Basicity is the ability of a compound to donate a pair of electrons. The more stable the conjugate acid, the weaker the base. The stability of the conjugate acid depends on the electron-donating/withdrawing groups present on the ring. The order of basicity of the given compounds is:
1. p-methoxyaniline
2. p-nitroaniline
3. aniline
4. p-toluidine
Reasoning:
p-methoxyaniline:
In p-methoxyaniline, the methoxy group (-OCH3) is an electron-donating group that increases the electron density on the nitrogen atom. This makes the lone pair of electrons on the nitrogen atom more available for protonation. Therefore, p-methoxyaniline is the most basic compound among the given compounds.
p-nitroaniline:
In p-nitroaniline, the nitro group (-NO2) is an electron-withdrawing group that decreases the electron density on the nitrogen atom. This makes the lone pair of electrons on the nitrogen atom less available for protonation. Therefore, p-nitroaniline is less basic than p-methoxyaniline.
aniline:
In aniline, there are no electron-donating or electron-withdrawing groups present on the ring. Therefore, aniline is less basic than p-methoxyaniline and p-nitroaniline.
p-toluidine:
In p-toluidine, the methyl group (-CH3) is an electron-donating group that increases the electron density on the nitrogen atom. However, it is not as effective as the methoxy group in p-methoxyaniline. Therefore, p-toluidine is less basic than p-methoxyaniline.
Therefore, the correct order of increasing basicity is: p-nitroaniline < aniline="" />< p-toluidine="" />< />
Option B: p-nitroaniline aniline p-toluidine p-methoxyaniline is the correct order of increasing basicity.
Basicity is the ability of a compound to donate a pair of electrons. The more stable the conjugate acid, the weaker the base. The stability of the conjugate acid depends on the electron-donating/withdrawing groups present on the ring. The order of basicity of the given compounds is:
1. p-methoxyaniline
2. p-nitroaniline
3. aniline
4. p-toluidine
Reasoning:
p-methoxyaniline:
In p-methoxyaniline, the methoxy group (-OCH3) is an electron-donating group that increases the electron density on the nitrogen atom. This makes the lone pair of electrons on the nitrogen atom more available for protonation. Therefore, p-methoxyaniline is the most basic compound among the given compounds.
p-nitroaniline:
In p-nitroaniline, the nitro group (-NO2) is an electron-withdrawing group that decreases the electron density on the nitrogen atom. This makes the lone pair of electrons on the nitrogen atom less available for protonation. Therefore, p-nitroaniline is less basic than p-methoxyaniline.
aniline:
In aniline, there are no electron-donating or electron-withdrawing groups present on the ring. Therefore, aniline is less basic than p-methoxyaniline and p-nitroaniline.
p-toluidine:
In p-toluidine, the methyl group (-CH3) is an electron-donating group that increases the electron density on the nitrogen atom. However, it is not as effective as the methoxy group in p-methoxyaniline. Therefore, p-toluidine is less basic than p-methoxyaniline.
Therefore, the correct order of increasing basicity is: p-nitroaniline < aniline="" />< p-toluidine="" />< />
Option B: p-nitroaniline aniline p-toluidine p-methoxyaniline is the correct order of increasing basicity.
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Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer?
Question Description
Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer?.
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Solutions for Arrange the following in order of increasing basicity: aniline, p – nitroaniline, p – toluidine,and p – methoxyanilinea)p – methoxyaniline p – nitroaniline < aniline < p – toluidineb)p – nitroaniline < aniline < p – toluidine < p – methoxyanilinec)aniline < p – methoxyaniline p – nitroaniline < p – toluidined)p – nitroaniline < aniline< p – methoxyaniline < p – toluidineCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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