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 For a given transistor, the thermal resistance is 8°C/W and for the ambient temperature TAis 27°C. If the transistor dissipates 3W of power, calculate the junction temperature (TJ).
  • a)
    51°C
  • b)
    27°C
  • c)
    67°C
  • d)
    77°C
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
For a given transistor, the thermal resistance is 8°C/W and for th...
We know, TJ-TA=HPD
TJ=TA+HPD=27+8*3=51°C.
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Most Upvoted Answer
For a given transistor, the thermal resistance is 8°C/W and for th...
Thermal resistance for a transistor is typically measured in degrees Celsius per watt (°C/W). It represents the ability of the transistor to dissipate heat and maintain a safe operating temperature.

In this case, the thermal resistance of the given transistor is 8 °C/W. This means that for every watt of power dissipated by the transistor, the temperature of the transistor will increase by 8 degrees Celsius.

A lower thermal resistance indicates better heat dissipation capabilities, allowing the transistor to operate at lower temperatures. Higher thermal resistance can lead to increased temperatures, potentially affecting the performance and reliability of the transistor.
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For a given transistor, the thermal resistance is 8°C/W and for the ambient temperature TAis 27°C. If the transistor dissipates 3W of power, calculate the junction temperature (TJ).a)51°Cb)27°Cc)67°Cd)77°CCorrect answer is option 'A'. Can you explain this answer?
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