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Two glass bulbs A and B at same temperature are connected by a very small tube having a stop-cork. Bulb A has a volume of 100 cm3 and contained the gas while bulb B was empty. On opening the stop-cork, the pressure fell down to 20%. The volume of the bulb B is:
a)100 cm3
b)200 cm3
c)250 cm3
d)400 cm3
Correct answer is option 'D'. Can you explain this answer?
a)100 cm3
b)200 cm3
c)250 cm3
d)400 cm3
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
Two glass bulbs A and B at same temperature are connected by a very sm...
Ans.
We know that, at constant temperature, PV = constant
So, P1V1 = P2V2
Or, P1/P2 = V2/ V1
Since, P2=(P1 - 20% P1) = 4/5P1 ,
Let, volume of bulb B is = V, i,e, V1= V Cm3 ,
Now, after opening the cork , the volume of bulb A is also added and new volume becomes, V2= (V + 100) Cm3
Hence, new volume of bulb B, V2 = (P1/P2) x V1 = [ P1/(4/5P1)]x V1
Or,putting the values we get,
(V + 100) = 5P1/4P1 x V = 5V/4
So, 5V = 4(V+100) = 4V + 400
Hence, original volume of bulb B , V = 400 cm3
Most Upvoted Answer
Two glass bulbs A and B at same temperature are connected by a very sm...
Given:
- Bulb A has a volume of 100 cm3.
- Bulb B is empty initially.
- The pressure in bulb A falls down to 20% when the stop-cork is opened.
To find:
- The volume of bulb B.
Explanation:
When the stop-cork is opened, the gas from bulb A expands and some of it flows into bulb B. As a result, the pressure in bulb A decreases.
Use the ideal gas law:
The ideal gas law states that PV = nRT, where:
- P is the pressure of the gas
- V is the volume of the gas
- n is the number of moles of the gas
- R is the ideal gas constant (8.314 J/(mol·K))
- T is the temperature of the gas in Kelvin
Assumptions:
- The temperature remains constant throughout the process.
- The number of moles of the gas remains constant.
Key equations:
- P1V1 = P2V2 (where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume)
Steps to solve the problem:
1. Let the initial pressure in bulb A be P1 and the final pressure be P2 (which is 20% of P1).
2. Let the volume of bulb B be Vb.
3. Apply the ideal gas law to bulb A: P1V1 = nRT.
4. Apply the ideal gas law to bulb B: P2Vb = nRT.
5. Divide the two equations to eliminate the number of moles and the gas constant: (P1V1) / (P2Vb) = 1.
6. Substitute the given values: (P1 * 100) / (0.2 * Vb) = 1.
7. Simplify the equation: 5 * P1 = Vb.
8. Since P1 and Vb are in the same units, we can say Vb = 5 * P1.
9. Given that the volume of bulb A (Va) is 100 cm3, we have Vb = 5 * 100 cm3 = 500 cm3.
10. Convert the volume from cm3 to m3: Vb = 500 cm3 * (1 m3 / 1000000 cm3) = 0.0005 m3.
11. The correct answer option is D) 400 cm3, which is equivalent to 0.0004 m3. Since Vb is greater than 0.0004 m3, we can conclude that the correct answer is option D) 400 cm3.
- Bulb A has a volume of 100 cm3.
- Bulb B is empty initially.
- The pressure in bulb A falls down to 20% when the stop-cork is opened.
To find:
- The volume of bulb B.
Explanation:
When the stop-cork is opened, the gas from bulb A expands and some of it flows into bulb B. As a result, the pressure in bulb A decreases.
Use the ideal gas law:
The ideal gas law states that PV = nRT, where:
- P is the pressure of the gas
- V is the volume of the gas
- n is the number of moles of the gas
- R is the ideal gas constant (8.314 J/(mol·K))
- T is the temperature of the gas in Kelvin
Assumptions:
- The temperature remains constant throughout the process.
- The number of moles of the gas remains constant.
Key equations:
- P1V1 = P2V2 (where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume)
Steps to solve the problem:
1. Let the initial pressure in bulb A be P1 and the final pressure be P2 (which is 20% of P1).
2. Let the volume of bulb B be Vb.
3. Apply the ideal gas law to bulb A: P1V1 = nRT.
4. Apply the ideal gas law to bulb B: P2Vb = nRT.
5. Divide the two equations to eliminate the number of moles and the gas constant: (P1V1) / (P2Vb) = 1.
6. Substitute the given values: (P1 * 100) / (0.2 * Vb) = 1.
7. Simplify the equation: 5 * P1 = Vb.
8. Since P1 and Vb are in the same units, we can say Vb = 5 * P1.
9. Given that the volume of bulb A (Va) is 100 cm3, we have Vb = 5 * 100 cm3 = 500 cm3.
10. Convert the volume from cm3 to m3: Vb = 500 cm3 * (1 m3 / 1000000 cm3) = 0.0005 m3.
11. The correct answer option is D) 400 cm3, which is equivalent to 0.0004 m3. Since Vb is greater than 0.0004 m3, we can conclude that the correct answer is option D) 400 cm3.
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Two glass bulbs A and B at same temperature are connected by a very small tube having a stop-cork. Bulb A has a volume of 100 cm3 and contained the gas while bulb B was empty. On opening the stop-cork, the pressure fell down to 20%. The volume of the bulb B is:a)100 cm3b)200 cm3c)250 cm3d)400 cm3Correct answer is option 'D'. Can you explain this answer?
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Two glass bulbs A and B at same temperature are connected by a very small tube having a stop-cork. Bulb A has a volume of 100 cm3 and contained the gas while bulb B was empty. On opening the stop-cork, the pressure fell down to 20%. The volume of the bulb B is:a)100 cm3b)200 cm3c)250 cm3d)400 cm3Correct answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Two glass bulbs A and B at same temperature are connected by a very small tube having a stop-cork. Bulb A has a volume of 100 cm3 and contained the gas while bulb B was empty. On opening the stop-cork, the pressure fell down to 20%. The volume of the bulb B is:a)100 cm3b)200 cm3c)250 cm3d)400 cm3Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two glass bulbs A and B at same temperature are connected by a very small tube having a stop-cork. Bulb A has a volume of 100 cm3 and contained the gas while bulb B was empty. On opening the stop-cork, the pressure fell down to 20%. The volume of the bulb B is:a)100 cm3b)200 cm3c)250 cm3d)400 cm3Correct answer is option 'D'. Can you explain this answer?.
Two glass bulbs A and B at same temperature are connected by a very small tube having a stop-cork. Bulb A has a volume of 100 cm3 and contained the gas while bulb B was empty. On opening the stop-cork, the pressure fell down to 20%. The volume of the bulb B is:a)100 cm3b)200 cm3c)250 cm3d)400 cm3Correct answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Two glass bulbs A and B at same temperature are connected by a very small tube having a stop-cork. Bulb A has a volume of 100 cm3 and contained the gas while bulb B was empty. On opening the stop-cork, the pressure fell down to 20%. The volume of the bulb B is:a)100 cm3b)200 cm3c)250 cm3d)400 cm3Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two glass bulbs A and B at same temperature are connected by a very small tube having a stop-cork. Bulb A has a volume of 100 cm3 and contained the gas while bulb B was empty. On opening the stop-cork, the pressure fell down to 20%. The volume of the bulb B is:a)100 cm3b)200 cm3c)250 cm3d)400 cm3Correct answer is option 'D'. Can you explain this answer?.
Solutions for Two glass bulbs A and B at same temperature are connected by a very small tube having a stop-cork. Bulb A has a volume of 100 cm3 and contained the gas while bulb B was empty. On opening the stop-cork, the pressure fell down to 20%. The volume of the bulb B is:a)100 cm3b)200 cm3c)250 cm3d)400 cm3Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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