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Which one of the following conditions on a group G implies that G is abelian?
  • a)
    The order of G is p3 for some prime p
  • b)
    Every proper subgroup of G is cyclic
  • c)
    Every subgroup of G is normal in G
  • d)
    The function f : G → G, defined by f(x) = x–1 for all x ∈ G, is a homomorphism
Correct answer is option 'D'. Can you explain this answer?
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Which one of the following conditions on a group G implies that G is a...
Explanation:

To prove that option 'D' implies that G is abelian, we need to show that if the function f : G -> G defined by f(x) = x^1 for all x in G is a homomorphism, then G is abelian.

1. The function f is a homomorphism:
To prove that f is a homomorphism, we need to show that f(xy) = f(x)f(y) for all x, y in G.

Let x, y be any elements in G. Then,
f(xy) = (xy)^1 = xy

f(x)f(y) = x^1y^1 = xy

Since f(xy) = f(x)f(y) for all x, y in G, we can conclude that f is a homomorphism.

2. Every homomorphism from G to G is given by conjugation:
It can be proven that every homomorphism from G to G is given by conjugation, i.e., for any homomorphism h : G -> G, there exists an element a in G such that h(x) = axa^(-1) for all x in G.

3. Every element in G commutes with every other element:
From the given information, we know that the function f : G -> G defined by f(x) = x^1 for all x in G is a homomorphism. From point 2, we can conclude that f(x) = axa^(-1) for all x in G, where a is some element in G.

Since f(x) = x^1 = x, we have x = axa^(-1) for all x in G.

This implies that every element in G commutes with every other element, i.e., G is abelian.

Therefore, option 'D' implies that G is abelian.

Conclusion:
The condition that the function f : G -> G defined by f(x) = x^1 for all x in G is a homomorphism implies that G is abelian.
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Which one of the following conditions on a group G implies that G is a...
Given that function mapping is homomorphism so it is one - one so G is abelian.
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Which one of the following conditions on a group G implies that G is abelian?a)The order of G is p3 for some prime pb)Every proper subgroup of G is cyclicc)Every subgroup of G is normal in Gd)The function f : G → G, defined by f(x) = x–1 for all x ∈ G, is a homomorphismCorrect answer is option 'D'. Can you explain this answer?
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